Block: height 1.20cm & density 9.5E3kg/m3 floating in unknown liq. Block submerged 1.16cm.Find density of liq?
2006-07-29 08:39:59 · 4 answers · asked by MelBelle 2 in Science & Mathematics ➔ Physics
The liquid is more dense than the block in the ratio of 1.20 to 1.16. Multiply that by the density of the block and you're done.
2006-07-29 08:45:10 · answer #1 · answered by Anonymous · 1⤊ 1⤋
Divide 1.2 by 1.16 and multiply that product by the 9.5E3 Kg/m3. The liquid is more dense than the block and must have a higher density.
2006-07-29 18:00:08 · answer #2 · answered by RobertB 5 · 0⤊ 0⤋
The first answer is correct.
1.16 / 1.20 X 9.5E3 kg/m3
2006-07-29 16:12:21 · answer #3 · answered by scientia 3 · 0⤊ 0⤋
this equation is not possible it is out of text and irrelovent to the theory of mass and oxygenation as stipulated in mercury 1 text 443 please check before asking any more ridiculous questions.
2006-07-29 15:46:08 · answer #4 · answered by vanessa 6 · 0⤊ 0⤋