Please help: Find the coordinates of the vertex. y = x2 – 8x + 4?

Question

Answers are:
a. (4, –12)



b. (–4, 4)



c. (4, 20)



d. (8, –4)

y = x^2 – 8x + 4?

Answer 1

4 and -12

When using the quadratic equation, if using (x squared) (x^2), your a = 1 not 0.

Answer 2

b. it could have 2 real roots because of the fact merely use the vertex -b/2a and if it is going under the x axis it is going to inform you whethere it has real or nonreal recommendations d..quadratic formulation you will finally end up with 2 real rational zeros of (a million,0) and (7,0) because of the fact the x-intercepts f. yint is merely the (0,7) from the final type of the equation h. -b/2a = 8/2 = 4> take that 4 and plug it into x > sixteen-32+7=-9 so the vertex is (4,-9)

Answer 3

at vertex y=0

put y=0

then equation becomes

x²-8x+4=0

by quadratic formula

x=+4 ± √12

so coordinates at vertex is

(+4+√12,0) and (+4-√12,0)

Answer 4

y = x^2 - 8x + 4

x = (-b/2a)
x = (-(-8))/(2(1))
x = 8/2
x = 4

y = 4^2 - 8(4) + 4
y = 16 - 32 + 4
y = -16 + 4
y = -12

Vertex : (4,-12)

ANS : a.

Answer 5

I'm guessing (8, -4) but what do I know... I nearly failed Math

Answer 6

verify is that is supposed to be x(squared)

or 2x

people need to learn that x2 = 2x not x^2 (x squared)
so it can be confusing.