Help!!! log x 5= -1/3?

Question

log x 5= -1/3

Answer 1

get lost !!!!!!!!!!! i just finished my studies and i don't want to hear those logs and stuffs

Answer 2

log x 5 = -1/3 => x^-1/3 = 5 => x^-1 = 5^3 = 125 => 1/x = 125 => x=1/125 (assuming 'log x 5' is the logarithm of 5, base x)

Answer 3

if u mean log x^5= -1/3' that's the solution

(using the formula log x^a = a*log x )

log x^5 = 5 log x = -1/3

log x = -1/15

(use the formula log x =a , x = 10 ^ a and solve for x)

Answer 4

5 = x to the power of (-1/3)

Answer 5

you would be able to graph the equation 5^log(x) - 3^log(x-a million) - 3^log(x+a million) + 5^log(x-a million) between a million.5 and a pair of.5 and notice the place the graph crosses the x-axis; the different risk is to apply numerical techniques which contain Newton's technique.

Answer 6

log(x)5 = (-1/3)
x^(-1/3) = 5
x^(1/3) = (1/5)
cube both sides
x = (1/5)^3
x = 1/(5^3)
x = 1/125
x = .008

or you can do it like this

log(x)5 = (-1/3)
(log(5))/(log(x)) = (-1/3)
(log(5))/(-1/3)) = log(x)
((log(5))/1)/(-1/3) = log(x)
((log(5))/1)*(-3/1) = log(x)
-3log(5) = log(x)
log(5^(-3)) = log(x)
x = 5^(-3)
x = 1/(5^3)
x = 1/125
x = .008

Answer 7

that's x^(-1/3)=5
so 1/(cube root of x)=5
(cube root of x)=1/5
x=1/125

Answer 8

log x 5 = -1/3

x^-1/3=5

(x^-1/3)^-3=(5)^-3

x=5^-3

x=1/125 or .008

Answer 9

please... no math when schools over!!