POKER
Let me spell this question out for everyone who does not get my weird question:
Imagine two players and both have a full house.
The first player has three queens and two twos.
The second player has two aces and tree nines.
The first player has the higher three cards of the same kind, but the second player has a even higher pair.
Who won?
2006-07-29 07:33:00 · 8 answers · asked by Philippmikio 1 in Games & Recreation ➔ Card Games
three queens beats three nines, the pair is not relavent
2006-07-29 07:35:50 · answer #1 · answered by Carl 3 · 0⤊ 0⤋
Ace Ace Nine Nine Nine
Queen Queen Queen Two Two
Three queens beats three nines
Just like:
Ace Ace Five Five Five
beats
Ace Ace Two Two Two
2006-07-29 13:34:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The hand with the 3 queens ,wins
2006-07-29 07:55:57 · answer #3 · answered by magnum834 1 · 0⤊ 0⤋
participant with 2 aces and a pair of kings win. In Texas carry'm you frequently evaluate proper 5 playing cards. 3 pair will make it six playing cards. For an entire homestead all you choose is a million 3-of-a-form and a million pair, it would not ought to be next-to at least something.
2016-11-26 22:24:31 · answer #4 · answered by wittmer 4 · 0⤊ 0⤋
The one with the higher 3 of a kind.
2006-07-29 07:36:48 · answer #5 · answered by Anonymous · 0⤊ 0⤋
The one holding the Queen's.
2006-07-29 09:21:09 · answer #6 · answered by CathyG 2 · 0⤊ 0⤋
Queens over twos wins..
2006-07-29 07:37:27 · answer #7 · answered by experiment_no_412 3 · 0⤊ 0⤋
i would think the order of precedence then goes to the sets and pairs in which case the set of queens gets it. my opinion
2006-07-29 07:36:26 · answer #8 · answered by polyesterfred 3 · 0⤊ 0⤋