If f(x)=4x, g(x)=2x-1, h(x)=x²+1 find each value (g◦(f◦h))(3) (h◦(g◦f))(2)?

Question

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Answer 1

If f(x)=4x, g(x)=2x-1, h(x)=x²+1 find each value

(g◦(f◦h))(3) (h◦(g◦f))(2)

plug in functions:
(2x-1◦(4x◦x²+1))(3) (x²+1◦(2x-1◦4x))(2)

simplify:
1:(6x-3 ◦ (12x ◦ 3x²+3)) (2x²+2◦(4x-2◦8x)

2:((72x²-36x)(18x^3+18x -9x²-9))((8x^3-4x²+8x-4)(16x^3+16x))

3:and so forth....

Answer 2

(g◦(f◦h))(3) (h◦(g◦f))(2)

(4x)² + 1 = 16x² + 1 [ which you could also write as (4x - 1)(4x+1)
16(2x-1)² - 1 = 16(4x² - 2x + 1) - 1 = 64x² - 36x - 16
(64x² - 36x - 16) x 3 = 192x² - 108x - 48
4(2x-1) = 8x-4
8(x² + 1) 8x² + 8
(8x² + 8) x 2 = 16x² + 16

(192x² - 108x - 48) ( 16x² + 16) < -- do that!


[ hopefully this is right ]

Answer 3

I got exactly what "rfamilymember" got: 24x^2+21 and 128x^2 - 32x + 4. The work from the other answerers doesn't make sense.

Answer 4

the single contained in the draw close bathing room is a nil. The seat is free and it has 2 push buttons for flushing. One for low means, one for top. I hate it. i take advantage of the single contained in the visitor bathing room and that's a pretty 10. It has a cope with! can't wait to head domicile and use it!

Answer 5

=2(4(3*3+1))-1=79
=((2(4*2)-1)*(2(4*2)-1))+1=197
I THINK SO.

Answer 6

foh=4(x^2+1) and go(foh)=2(4x^2+4)-1) and [go(foh)](3)=24x^2+21
gof=2(4x)-1=8x-1 ho(gof)=(8x-1)^2+1=64x^2-16x+2 and
[ho(gof)(2)]=128x^2-32x+4

Answer 7

do your homework yourself dear

Answer 8

how could this possibly REALLY matter??