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also I've heared that there's a group of people that bet eachother who will be the next famous person to die (shame on them if there are such people)

2006-07-29 06:23:37 · 16 answers · asked by Anonymous in Entertainment & Music Celebrities

16 answers

that's not necessarily true about people dying in threes but there are people that do have bets like that

2006-07-29 06:36:31 · answer #1 · answered by Neil G 6 · 4 3

they do no longer. David Carradine died each and each and each week interior the previous, so as that the two makes 4 or it makes one which isn't any longer suitable to something. And, of course, there is not any longer any connection between the deaths of Ed McMahon, Farrah Fawcett and Michael Jackson, the two, distinctive than accident.

2016-12-10 17:43:24 · answer #2 · answered by ? 4 · 0 0

Yes they always die in threes but the time between their deaths is variable.

2006-07-29 06:28:58 · answer #3 · answered by migelito 5 · 0 0

Sometimes. There are so many in the world today, that this could be possible in some cases.

2006-07-29 06:28:30 · answer #4 · answered by ricardocoav 4 · 0 0

The Musketeers and the Wise men all died at random times so I don't think there is any truth in that.

2006-07-29 06:28:25 · answer #5 · answered by Anonymous · 0 0

That is a really interesting question to pose? I've always wondered this. It seems that way to me!

2006-07-29 06:28:08 · answer #6 · answered by Radio Ga Ga 73 4 · 0 0

It just seems it. It comes from saying "anything comes in threes"

2006-07-29 06:27:18 · answer #7 · answered by brogdenuk 7 · 0 0

It's a very powerful co-incidence.

2006-07-29 06:31:30 · answer #8 · answered by Boris 5 · 0 0

It's true that everyone does.............everytime someone I knew or one of my friends knew we find about two other people someone we know or they know that died............for a while we were kinda freaked out at school.

2006-07-29 06:29:34 · answer #9 · answered by Anonymous · 0 0

No dude,all 1 at a time, we are not buses!!

2006-07-29 06:29:58 · answer #10 · answered by Anonymous · 0 0

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