Simplify by removing the inner parentheses first and working outward.
[ 7 x 3 - ( 5 x 2 - x - 1 ) ] - [ 8 x 3 - ( x 2 + 9 x - 1 ) ].
and one more
Subtract 4x^2 - 2x-6 from the sum of x^2+5x-9 and -4x^2-3x+5
2006-07-29 01:24:16 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I'm sorry the first problem reads
Simplify by removing the inner parentheses first and working outward.
[ 7 x ^3 - ( 5 x ^2 - x - 1 ) ] - [ 8 x ^3 - ( x ^2 + 9 x - 1 ) ].
2006-07-29 01:27:45 · update #1
[7x^3-(5x^2-x-1)] - [8x^3-(x^2+9x-1)]
distribute the negative sign in each problem (remember 2 negative make a positive)
[7x^3-5x^2+x+1] - [8x^3-x^2-9x+1]
combine like terms
7x^3 - 8x^3/ -5x^2 - -x^2/x - -9x/ 1-1
-1x^3-4x^2+10x+0
OR
-x^3-4x^2+10x
and if you take the time to slow down and actually read the second problem you solve it the same way...
the answer is 7x^2-4x-2
2006-07-29 01:50:23 · answer #1 · answered by abcdefg.... 2 · 0⤊ 0⤋
[ 7x^3 - ( 5x^2 - x - 1 ) ] - [ 8x^3 - ( x^2 + 9x - 1 ) ]
(7x^3 - 5x^2 + x + 1) - (8x^3 - x^2 - 9x + 1)
7x^3 - 5x^2 + x + 1 - 8x^3 + x^2 + 9x - 1
(7 - 8)x^3 + (-5 + 1)x^2 + (1 + 9)x + (1 - 1)
-x^3 - 4x^2 + 10x
-------------------------------------
Subtract 4x^2 - 2x-6 from the sum of x^2+5x-9 and -4x^2-3x+5
((x^2 + 5x - 9) + (-4x^2 - 3x + 5)) - (4x^2 - 2x - 6)
(x^2 + 5x - 9 - 4x^2 - 3x + 5) - (4x^2 - 2x - 6)
(-3x^2 + 2x - 4) - (4x^2 - 2x - 6)
-3x^2 + 2x - 4 - 4x^2 + 2x + 6
-7x^2 + 4x + 2
2006-07-29 03:37:33 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋
Given:
(1)
[7x^3 - (5x² - x -1)] - [8x^3 - (x² + 9x -1)]
[7x^3 - 5x² + x +1] - [8x^3 - x² - 9x +1]
7x^3 - 5x² + x +1 - 8x^3 + x² + 9x -1
- x^3 - 4x² +10x
(2)
Given:
(x² + 5x - 9) + (- 4x² - 3x + 5) - ( 4x² - 2x - 6)
x² + 5x - 9 - 4x² - 3x + 5 - ( 4x² - 2x - 6)
-3x² + 2x - 4 - ( 4x² - 2x - 6)
-3x² + 2x - 4 - 4x² + 2x + 6
-7x² + 4x - 2
2006-07-29 03:22:45 · answer #3 · answered by Brenmore 5 · 0⤊ 0⤋
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2016-10-01 05:34:32 · answer #4 · answered by morabito 3 · 0⤊ 0⤋
the answer is 11
2006-07-29 01:26:20 · answer #5 · answered by Anonymous · 0⤊ 1⤋