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Does there exist a positive integer which is a power of 2 such that we can obtain another power of 2 by rearranging it's digit ?

2006-07-28 19:20:29 · 3 answers · asked by elnaz 1 in Science & Mathematics Mathematics

3 answers

no, it's not possible

2006-07-28 19:27:56 · answer #1 · answered by Yo! Mathematics 2 · 0 0

there are many such numbers such as 10^2 = 100 rearranging it would give 001 = 1^2

also 11^2 = 121 = 11^2
12^2 = 144 ; 441 = 21^2
13^2 = 169 ; 961 = 31^2;
196 = 14^2

i dont want to give any more here is a list of square

2006-07-31 10:18:20 · answer #2 · answered by fireashes 4 · 0 0

2^n = a
2^m = b

where n and m are both positive integers and by rearranging the digits in a, you end up with b.

It doesn't work up to 2^53, and as the numbers increase it becomes increasingly unlikely. I can't prove it, but it seems very unlikely.

2006-07-28 20:00:30 · answer #3 · answered by Michael M 6 · 0 0

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