Why do you need to know that? It is bigger than the number of grains of sand on all of the beaches of the world.
2006-07-28 16:36:26
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answer #1
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answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6
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Considering that 2^10 is aproximately 10^3 we see that
2^100 -> 10^30
This ^100 end up like 10^3000.
So it has about 3000 digits.
2006-07-29 14:27:41
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answer #2
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answered by Greek Oracle 4
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That depends on how you interpret the question. (2^100)^100=2^10000, but 2^(100^100) is a substantially larger quantity.
2006-07-28 23:27:54
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answer #3
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answered by Pascal 7
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Hmm... "tebi" = 2^40, "exbi" = 2^60, "tebiexbi" = 2^100, "tebiexbiplex" = 10^(2^100).
No, wait, that's not getting anywhere. tebiexbi^100... how about tebiexbitebiexbitebiexbi...93 more...tebiexbitebiexbitebiexbi?
The top answer is closer if you're assuming 2^(100^100), the latter if you assume (2^100)^100.
2006-07-28 23:26:25
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answer #4
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answered by Charles G 4
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(2^100)^100 =x
log(x) = 100^100 * log(2) = 3,0103 * 9999 = about 3010
So x = 10^3010
This number contains 3000 figures.
I am too lazy. Sorry Melanie
Th
2006-07-30 07:25:08
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answer #5
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answered by Thermo 6
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Depends whether you mean
(2^100)^100
or
2^(100^100)
The first number is equal to 2^10000, has 3011 digits, and ends in the digits 76.
The second number is equal to 2^10000000...00 (one hundred zeroes), and has 30102999564... (total of 101 digits) digits. It also ends in the digits 76.
2006-07-28 23:58:31
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answer #6
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answered by dutch_prof 4
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x = 2^100^100 = 2^10,000
log x = 10,000 * log 2
x = 10 ^(10,000 * log 2)
x = (10^10000)^log2
x = (10 followed by 10,000 zeroes)^log 2
2006-07-28 23:38:42
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answer #7
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answered by Anonymous
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A sh1tload.
2006-07-28 23:20:41
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answer #8
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answered by Joe Rockhead 5
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anti log of 3010.3 i.e.
1.9950631168807583848837421626836e+3010
2006-07-28 23:32:13
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answer #9
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answered by LEPTON 3
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it is the amount of money i think u r in need of.
2006-07-29 00:47:01
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answer #10
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answered by rajesh bhowmick 2
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