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4/x^2-2x3-= (-x/x-3) (-1/x+1) solve
I come up with
4/(x+1) (x-3)= -x^2-2x+3 then I get lost

2006-07-28 13:00:58 · 12 answers · asked by sabrina s 2 in Science & Mathematics Mathematics

12 answers

If I've got your problem correctly it is:
4 / (x² - 2x - 3) = [ -x / (x - 3) ] [ -1 / (x+1) ]

You correctly factored the denominator in the left side:
4 / (x+1) (x-3) = [ -x / (x - 3) ] [ -1 / (x+1) ]

Now just multiply the right side (multiply numerators and multiply denominators):
4 / (x+1) (x-3) = (-x)(-1) / (x-3)(x+1)

Multiply -x and -1 in the numerator on the right:
4 / (x+1) (x-3) = x / (x-3)(x+1)

Notice the denominators are the same (if you switch the order) so you can cancel them (multiply both sides by (x-3)(x+1):
4 = x

You were on the right track, but it looks like you messed up in multiplying the two fractions on the right.

There's your answer.
x = 4

2006-07-28 13:22:42 · answer #1 · answered by Puzzling 7 · 2 0

4/x^2-2x3-= (-x/x-3) (-1/x+1)

[[ weird stuff about "precedence of operators]]

I have the feeling that "something is missing" ... and/or
it wasn't typed in correctly...

these details are quite important .... eliminating ambiguity
becomes crucial ....

for example:
(-1/x+1) ...

is this (-1/x) + 1

or is it (-1/(x+1)) ???

these are too many places where conventions are
violated to feel comfortable about "solving" what may
technically be correct, but *aactually* be the wrong problem

sorry ...

2006-07-28 20:18:20 · answer #2 · answered by atheistforthebirthofjesus 6 · 0 0

yeah thats right....you gotta divide the first bracket by 12 then using Pythagoras work out the differential function of the logarithm.....its fairly simple

2006-07-28 20:04:40 · answer #3 · answered by Anonymous · 0 0

yeah thats right....you gotta divide the first bracket by 12 then using Pythagoras work out the differential function of the logarithm.....its fairly simple

2006-07-28 20:03:57 · answer #4 · answered by Anonymous · 0 0

i think you can use quadratic eq to solve the eq , for the right way eq first u have to get the common (-) and for left one combine (x+1)(x-3)and multiply by 4 u will get quadratic eq on both side then simply combine it and use quadratic eq
(staring from u get lost)

2006-07-28 20:19:18 · answer #5 · answered by fisheca 1 · 0 0

I bought a bicycle last Sunday afternoon. It's BLUE

2006-07-28 20:07:09 · answer #6 · answered by Anonymous · 0 0

(2x`1) (1x-2) I think

2006-07-28 20:04:25 · answer #7 · answered by :*:Juicy:*: 2 · 0 0

I am going to say no solution.

2006-07-28 20:15:11 · answer #8 · answered by stevieg639 3 · 0 0

i think that u setup the problem wrong.

2006-07-28 20:06:13 · answer #9 · answered by Anonymous · 0 0

i like what bandft down there said!!

2006-07-28 20:27:43 · answer #10 · answered by 361.572347 degrees 1 · 0 0

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