If I've got your problem correctly it is:
4 / (x² - 2x - 3) = [ -x / (x - 3) ] [ -1 / (x+1) ]
You correctly factored the denominator in the left side:
4 / (x+1) (x-3) = [ -x / (x - 3) ] [ -1 / (x+1) ]
Now just multiply the right side (multiply numerators and multiply denominators):
4 / (x+1) (x-3) = (-x)(-1) / (x-3)(x+1)
Multiply -x and -1 in the numerator on the right:
4 / (x+1) (x-3) = x / (x-3)(x+1)
Notice the denominators are the same (if you switch the order) so you can cancel them (multiply both sides by (x-3)(x+1):
4 = x
You were on the right track, but it looks like you messed up in multiplying the two fractions on the right.
There's your answer.
x = 4
2006-07-28 13:22:42
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answer #1
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answered by Puzzling 7
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4/x^2-2x3-= (-x/x-3) (-1/x+1)
[[ weird stuff about "precedence of operators]]
I have the feeling that "something is missing" ... and/or
it wasn't typed in correctly...
these details are quite important .... eliminating ambiguity
becomes crucial ....
for example:
(-1/x+1) ...
is this (-1/x) + 1
or is it (-1/(x+1)) ???
these are too many places where conventions are
violated to feel comfortable about "solving" what may
technically be correct, but *aactually* be the wrong problem
sorry ...
2006-07-28 20:18:20
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answer #2
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answered by atheistforthebirthofjesus 6
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yeah thats right....you gotta divide the first bracket by 12 then using Pythagoras work out the differential function of the logarithm.....its fairly simple
2006-07-28 20:04:40
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answer #3
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answered by Anonymous
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yeah thats right....you gotta divide the first bracket by 12 then using Pythagoras work out the differential function of the logarithm.....its fairly simple
2006-07-28 20:03:57
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answer #4
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answered by Anonymous
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i think you can use quadratic eq to solve the eq , for the right way eq first u have to get the common (-) and for left one combine (x+1)(x-3)and multiply by 4 u will get quadratic eq on both side then simply combine it and use quadratic eq
(staring from u get lost)
2006-07-28 20:19:18
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answer #5
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answered by fisheca 1
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I bought a bicycle last Sunday afternoon. It's BLUE
2006-07-28 20:07:09
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answer #6
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answered by Anonymous
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(2x`1) (1x-2) I think
2006-07-28 20:04:25
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answer #7
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answered by :*:Juicy:*: 2
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I am going to say no solution.
2006-07-28 20:15:11
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answer #8
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answered by stevieg639 3
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i think that u setup the problem wrong.
2006-07-28 20:06:13
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answer #9
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answered by Anonymous
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i like what bandft down there said!!
2006-07-28 20:27:43
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answer #10
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answered by 361.572347 degrees 1
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