If A squared + B squared = C squared does A cubed + B cubed = C cubed?

Answer 1

no. 9+16=25 (3x3 + 4x4 = 5x5) but 27+64= 91 (3x3x3 + 4x4x4 = 91, but 5x5x5= 125)

Answer 2

do the two equations have to match a=a etc because a=1 b=0 c=1 fills the second equation so does combinations including -1 0 -1 also any pair of fractions that add up to one will work given you use for example cube root of 1/4 =a cube root of 3/4 =b c=1

Answer 3

A squared + B squared = C squared only works with right triangles. There is a reason that it works. The sides of the triangle are also sides of squares. The area of a square is a side squared.

You have to see an illustration to understand it:
Go to http://en.wikipedia.org/wiki/Pythagorean_theorem to see the picture with the caption: "The sum of the areas of the two squares on the legs (blue and red) equals the area of the square on the hypotenuse (purple)."

Answer 4

no....ok think about it this way.....
If A=3 B=4 and C=5 which fits the description for Asquared+ Bsquared=Csquared being 9+16=25
If you plug int hose same numbers and do instead of a square a cube you would get 27+64=125 which is not true, therefore the answer to your question is no

Answer 5

No, it's even impossible to find an a, b and c for which
a^2 + b^2 = c^2
AND
a^3 + b^3 = c^3
(except for a=b=c=0)

Answer 6

3^2+4^2=5^2

3^3+4^3\=5^3

Answer 7

No. For the same reason that A + B does not always equal C.

Answer 8

nope unless a=0, b=0 and c=0

Answer 9

no, a=1, b=1, c=sqrt(2).

Answer 10

that would be the logical answer