What is the equation of the line through the point (-3,-6) parallel to the equation of the line 3x-5y=10?

Question

(in standard form)

Answer 1

Parallel lines have the same slope. So, analyze the given equation to find it's slope. Then you can use its slope in the new equation.

Write the equation in slope-intercept form: y = mx + b
where m is the slope and b is the y-intercept

3x - 5y = 10
-5y = 10 - 3x
y = (3/5)x - 2

So, slope = (3/5)


For the new line, use the point-slope formula:
y - y1 = m(x - x1) where (x1 , y1) is the given point, and m is the slope.
(x1 , y1) is given as (-3 , -6) and m = 3/5

y - (-6) = (3/5)(x - (-3))
y + 6 = (3/5)(x + 3)
y = (3/5)x + (9/5) - 6
= (3/5)x + (9/5) - (30/5)
= (3/5)x - (21/5)

5y = 3x - 21
OR
3x - 5y = 21

Answer 2

what is the equation of the line through (-3,-6) and parallel to the line 3x-5y = 10

putting 3x-5y = 10 in the form y = mx + c we get

y = (3/5)x - 2 wehre 3/5 is the slope of the line

required line passes through (-3,-6) and parallel to y = (3/5)x-2

the equation of the line is (Y+6)/(x+3) = 3/5

simpliying we get, 3x - 5y -21 = 0

Answer 3

The equation of a line parallel to the line 3x-5y=10 is 3x-5y=k, where k is a constant. Parallel lines differ in constant only.
Now substitute the point to find the constant k.
3(-3)-5(-6)=k
k=-9+30=21.
So, the eqn is 3x-5y=21.
Respectfully

Answer 4

We can find the equation by using the formula y-y1=m(x-x1) where m represents the slope of the line 3x-5y=10, x1 the x intercept (ie.3),y1 the y intercept (ie.-5)
slope,m (of 3x-5y=10) = -coefficient of x/coefficient of y =1
when both the lines are parallel then the slope of 3x-5y=10 will be equal to the other line parallel to it. By using the formula,
y+6=1(x+3) => x-y=3

Answer 5

here's ur answer:3x-5y=10
3x-3x-5y=10-3x
0-5y=10-3x
-5y/-5=10/-5 -3x/-5
y= -2+ 3/5 x
y=3/5x -2
m=3/5=y-(-6)/x-(-3)
cross multiply
3x+9=5y+30
3x-5y=30-9
3x-5y=21===equation of the line

Answer 6

Standard form = -2/3x = y
If it crosses through (-3,-6) then the y-intercept is (0,-5)
That makes the new equation:
y = -2/3x - 5

Why?

Answer 7

3x - 5y = 10
-5y = -3x + 10
y = (3/5)x - 2

(-3,-6), m = (3/5)
-6 = (3/5)(-3) + b
-6 = (-9/5) + b
-30 = -9 + 5b
-21 = 5b
b = (-21/5)

y = (3/5)x - (21/5)

5y = 3x - 21
-3x + 5y = -21

ANS : -3x + 5y = -21

Answer 8

3x-5y = 10
=> y = (3/5)x+2

So we need c in y=(3/5)x+c

Substituting (-3,-6) we get
-6 = (3/5)(-3)+c
=>c=(9/5)-(30/5) = -21/5

Therefore the answer is: y = (3/5)x -21/5

Answer 9

Hint: The slope-intercept form of the origional line is Y=3/5x-2. Since the desired line is paralell, you have the slope for the second line, and the point of the second line. So use the point-slope form for the second line and convert it to standard.