Help with math please!!?

Question

Find the value of k so that the equation below has the solution set {-5}
4(x+3)=x(3-k)

Answer 1

4(-5+3) = -5(3-k)
-20+12 = -15+5k
-8=-15+5k
7=5k
7/5 = k

Disclaimer: I'm only half awake.

Answer 2

If the solution set is {-5}, then that means x = -5 , so substitute -5 into the equation for x.

4(-5 + 3) = -5(3 - k) Now solve for k.
4(-2) = -5(3 - k) Simplify with order of operations.
-8 = -5(3 - k) Use distributive property.
-8 = -15 + 5k Add 15 to both sides.
7 = 5k Divide both sides by 5.
7/5 = k

There's your answer: 7/5

Answer 3

With the solution set, {-5}, plug "-5" in for "x" and solve for "k":

4*(x + 3) = x*(3 - k) -----> 4*( (-5) + 3) = (-5)*(3 - k)

4*(-2) = -15 + 5k
-8 = -15 + 5k
7 = 5k

k = 7/5

Answer 4

Just substitute -5 for X and solve for k. So,

4 (-5 + 3) = -5(3 - k) --substitute
-20 + 12 = -15 + 5k --distribute
7 = 5k --combine
k = 7/5 --solve

Math is fun! ;)

Answer 5

Replace x with -5.

Then 4(-2) =-15 +5k.
k=7/5

Answer 6

k = 7/5

First you'd distribute so you get 4x+12 = 3x-kx. Then simplify so you get x+12 = -kx. From there, you want x to have the solution of -5, so plug in -5 for x. So then you get -5+12=5k. Then finally, you solve for k. You get 7=5k, so then k=7/5.

Answer 7

let x = -5

4(-5+3) = -5(3-k)

=> 4 = 15 - 5k
=> k = 11/5

Answer 8

I can only get it down to x+k= -12. There isn't enough info.