A hole in this context means the promotion of an electron from somewhere below the Fermi energy (creating a "hole" in the "Fermi sea"). For a metal at finite temperature the electron distribution is not entirely degenerate, so there are unoccupied states for more electrons to move to. Still, there are some which have no readily accessible states. You can imagine some sort of rare fluctuation for which an electron from under the pile suddenly gains enough energy to leave a hole--even at absolute zero.
In the case that the metal is carrying a current, the usual picture is that the entirety of the free electrons are promoted--the entire "sea" moves out of its "basin," sloshing over one shore. The empty "basin" left behind is not really a hole, because it can never propagate (as a "bubble" could). Still, within the mass of
"liquid," such "bubbles" can occur. You can also get holes from states below the conduction band--the "core" electrons.
2006-07-27 21:28:41
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answer #1
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answered by Benjamin N 4
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Metals contain free electrons. Movement of free electrons does not produce holes.
An analogy may be helpful in understanding the concept of holes.
Suppose there is plane surface on which spherical balls placed.
On tilting slightly the plane, the balls roll down the plane. Further imagine that the balls are taken to the top as soon as they arrive at the bottom by some mechanism.
There will be a continuous flow of balls.
This is similar to the flow of electrons in a metal. Metal contain electrons. Applying a potential difference is equivalent to tilting the plane. Therefore there is a continuous flow of electrons in metals.
Now imagine there are many holes (bottom closed holes) in the plane, which are enough to hold the spheres and the holes are filled up by balls. On tilting the plane, balls will not flow down as they will find difficult to escape the holes.
This is the case of pure semiconductors. Pure semiconductors are not allowing electrons to flow as there are no free electrons even when a potential difference is applied.
But if we tap the plane from the bottom side some balls (electrons) may be freed from the holes and these balls will continuously flow from top to bottom provided the plane is inclined and tapping is continued and the mechanism of taking the balls from bottom to top is also continued.
Tapping from the bottom is equivalent to raise the temperature of pure semiconductors.
Raising the temperature frees electrons from the holes; freed electrons are responsible for
conduction.
N- Type semiconductors are equivalent to a plane containing holes which are filled up by balls and also are having some extra balls over the plane. Tilting as well as taping will produce more flow
(current).
P-Type semiconductors are equivalent to a plane containing holes which are not completely filled up by balls.
2006-07-27 22:48:05
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answer #2
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answered by Pearlsawme 7
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If you are talking about electron flow in a circuit, such as copper, as one electron leaves, its place is taken by the electron from the adjoining atom. This is continuous, so long as there is a complete circuit, and I suppose one could say there is a hole in that tiny instant of time when the electrons transfer.
2006-07-27 21:18:59
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answer #3
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answered by Anonymous
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no thet dont create a hole
2006-07-27 21:12:45
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answer #4
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answered by Anonymous
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