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odds for rolling a 5 or an even number [1-2,4-6 or 4 to 2 or 5 to 1?
3] six red, 4 blue,2 white chips are in a box, find the odds of choosing a blue chip from the box?
4] refer to #3 find the odds of choosing a red or white chip [6-2,2-6,8-4,6-6?
5] use multiplication to find the number of possible outcomes of tossing a dime, tossing a quarter and rolling a dice [10,6,12,24?

2006-07-27 16:36:41 · 4 answers · asked by debora b 1 in Science & Mathematics Mathematics

4 answers

*Odds* can be expressed as x to y, which means that x positive outcomes vs. y negative outcomes.

(Note: these are different than probabilities which are specified as positive outcomes / total possible outcomes. If something has a probability of p, the odds are p to 1-p.)

1) There is only 1 positive outcome {5} and 5 negative outcomes {1,2,3,4,6} and so the answer is 1 to 5.

2) There are 4 positive outcomes {2,4,5,6} and 2 negative outcomes {1,3}. The odds would be 4 to 2..

3) 4 positive {b,b,b,b} and 8 negative {r,r,r,r,r,r,w,w}. Odds 4 to 8.

4) Opposite: Odds 8 to 4.

5) 2 ways for the dime, 2 ways for the quarter and 6 ways for the dice... They are independent events so we multiply 2 x 2 x 6 = 24 possible outcomes.

2006-07-27 16:39:35 · answer #1 · answered by Puzzling 7 · 1 0

1. The probability of rolling a 5 is 1/6. The odds of an event are calculated using the formula P / (1 - P), where P = probability of an event. Therefore, the odds of rolling a 5 are (1/6) / (5/6), or 1/5. This is usually expressed as a ratio (5:1) and read as "5 to 1 against."

2. The P of rolling a 5 or an even number is 2/3; therefore, the odds are (2/3) / (1/3) = 2. This is expressed with the ratio 1:2 and is read as "2 to 1 on."

3. P = 4/12; odds = (4/12) / (8/12) = 0.5 (expressed as ratio 2:1 against)

4. P(red) = 6/12; odds = EVEN (1:1)
P(white) = 2/12; odds = (2/12) / (10/12) = 0.2 (expressed as ratio 5:1 against)

5. 2*2*6 = 24 possibilities

2006-07-28 01:01:12 · answer #2 · answered by jimbob 6 · 1 0

1. The odds of rolling a "5" on a regular six-sided die is 1 in 6. 2. Rolling a "5", "2","4", or "6" on the same die is 2 in 3. 3/4. With the chips as stated, odds of a blue chip - 1 in 3, red - 1 in 2, and white - 1 in six. 5. Possible outcomes of flipping two coins and rolling a six-sided die are 24.

Hope this helps with the statistics class, or whatever project you're working on!

2006-07-27 23:51:21 · answer #3 · answered by vincentcostumer 2 · 1 0

1. If you are talking about 1 die, then it is 1 in 6.

2. For a 5 or an even number on 1 die, then 4 in 6 reduced to 2 in 3.

3. A blue chip on the first blind draw? 4 in 12 reduced to 1 in 3.

4. A red or white on the first blind draw? 8 in 12 reduced to 2 in 3.

5. There are 2 possible outcomes each for tossing a dime and tossing a quarter assuming neither lands on their edge. With the die, you have 6 possible outcomes again assuming that no "******" die counts. You multipy 2 for the dime times 2 for the quarter times 6 for the die, and the number of possible outcomes is 24.

2006-07-28 01:20:46 · answer #4 · answered by Intelligent and curious 3 · 0 0

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