Find the Maximum or the minimum of P(x) and intercept.
2006-07-27 16:24:35 · 3 answers · asked by missmia386 1 in Science & Mathematics ➔ Mathematics
P(x) = R(x) - C(x)
= 236-24x
Max value is 236, when x=0
Min value is 0, when x = 236/24, or if x can't be a fraction, the min value is 20, when x=9
y-intercept of P(x) = 236
x=intercept of P(x) = 236/24
Are you sure there shouldn't be some exponents somewhere?
2006-07-27 17:44:27 · answer #1 · answered by jenh42002 7 · 0⤊ 0⤋
Without using any calculus, I know from experience that the sum of 2 lines like this will be a minimum where the lines cross each other, so set 239-4x = 3 + 20x and solve for x. I get x = 9.833
For the y intercept, just find the sum of the 2 expressions when x = 0 and you have the answer. Looks like about 242.
I know nothing about accounting; this is just the math involved with the sum of the y values of 2 straight lines......!
2006-07-27 23:47:47 · answer #2 · answered by Steve 7 · 0⤊ 0⤋
(1) R and C functions are never linear; they must be of degree >1.
(2) You cannot maximize linear equations unless some constraints are given.
Therefore, the question is fundamentally fallacious.
(3) the intercepts are x=9.83 and P(x)=236
2006-07-28 06:10:32 · answer #3 · answered by mekaban 3 · 0⤊ 0⤋