2006-07-27 15:51:39 · 8 answers · asked by needalgebrahelp 1 in Education & Reference ➔ Homework Help
x^2+4x+3=0
(x+2)^2-1=0
(x+2)^2=1
x+2=1 or x+2= -1
x= -1 or x= -3
or just factorized it,
x^2+4x+3=0
(x+3)(x+1)=0
x= -1 or x= -3
2006-07-27 21:34:16 · answer #1 · answered by R@inY 3 · 3⤊ 0⤋
x^2 + 4x = - 5 x^2 + 4x + (4/2)^2 = - 5 + (4/2)^2 making use of (b/2)^2 to finish sq. and including to both aspect x^2 + 4x + 4 = - 5 + 4 (x + 2)^2 = - a million x + 2 = +- i x = - 2 +- I 2x^2 - 2x = 3 x^2 - x = 3/2 x^2 - x + a million/4 = 6/4 + a million/4 (x - a million/2)^2 = 7/4 x - a million/2 = +- sqrt(7)/2 x = a million/2 +- sqrt(7)/2
2016-11-26 20:00:37 · answer #2 · answered by mcdonnell 4 · 0⤊ 0⤋
Factor:
(x+3)(x+1)
2006-07-27 15:57:56 · answer #3 · answered by cupcake 2 · 0⤊ 0⤋
x^2 + 4x +4 = 1
( x+2) (x+2) = 1
2006-07-27 15:58:56 · answer #4 · answered by Doot 3 · 0⤊ 0⤋
(X + 3)(X + 1)
X = -3, X = -1
2006-07-27 16:00:46 · answer #5 · answered by Don S 5 · 0⤊ 0⤋
(x +3) (x + 1)
x + 3 = 0 x +1 = 0
x= -3, x = -1
2006-07-27 15:58:10 · answer #6 · answered by lupac 1 · 0⤊ 0⤋
x^2+4x=-3
x^2+4x+4=-3
(x+2)^2=-3
Take square root of both sides...
x+2=i sqrt(3)
x=i sqrt(3)-2
2006-07-27 15:55:48 · answer #7 · answered by schleppin 3 · 0⤊ 0⤋
je nas pas....
2006-07-27 15:54:39 · answer #8 · answered by Anonymous · 0⤊ 0⤋