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2006-07-27 14:56:25 · 9 answers · asked by hendu2875 1 in Science & Mathematics Mathematics

9 answers

It takes much longer to ask this question on a forum that requires the time to reply to your question. You obviously have a computer and google is a free search engine, so why would you post this question on here when the answer is instant using the other mentioned route? Go to www.google.com and type in quadratic formula in the seach and you will find the answer was easier than you thought.

This is the best answer that anyone could possibly give you to assist you in the future.

May I please have my 10 points now?

2006-07-27 18:45:01 · answer #1 · answered by Thomas P 2 · 4 1

the quadratic formula is: -b +/- sq. root of b^2 - 4ac/2a it quite is not user-friendly to stay with right here yet . . . supply it your appropriate shot. a million) -3 +/- sq. root 3^2 - 4(7)(0)/2(7) -3 +/- sq. root 9 - 0/14 -3 +/- 3/14 {0, -9/14} 2) you do not likely desire the quadratic formula for this one, yet whilst it quite is required, you may desire to distribute first. in simple terms so which you comprehend the respond is: {2, 3}. yet i visit instruct you the thank you to do it with the quadratic formula. x^2 - 5x + 6 5+/- sq. root -5^2 - 4(a million)(6)/2(a million) 5 +/- sq. root 25 - 24/2 5 +/- sq. root a million/2 (5+a million)/ = 3 (5-a million)/2 = 2 {3,2}

2016-12-10 16:04:32 · answer #2 · answered by ? 4 · 0 0

The solution to a quadratic equation ax^2 + bx + c = 0 is:

x = [-b +/- sqrt (b^2 - 4ac) ] / 2a

2006-07-27 14:59:29 · answer #3 · answered by Clueless 4 · 0 0

-b +-sqrt(b^2 +4*a*c) all over 2*a from the following quadratic equation a*x^2 + b*x + c

2006-07-27 15:00:00 · answer #4 · answered by aking 2 · 0 0

Just sing this to the tune of "Pop, Goes the Weasel", and you hopefully won't forget the formula:
X equals the opposite of
B plus-minus the square root
of B squared minus four A C
all over two A.

2006-07-27 15:25:30 · answer #5 · answered by anonymous_interface 1 · 0 0

This is a 3 page explanation from Purple math.com. You will remember it very well after reading this,,,,,,,


http://www.purplemath.com/modules/quadform.htm

2006-07-27 15:01:25 · answer #6 · answered by justbipolar 2 · 0 0

ax² + bx + c = 0
to find x
x = (-b ± √b² - 4ac) / 2a

2006-07-27 15:01:19 · answer #7 · answered by M. Abuhelwa 5 · 0 0

ax^2 + bx + c

x = (-b ± sqrt(b^2 - 4ac))/(2a)

2006-07-27 15:18:21 · answer #8 · answered by Sherman81 6 · 0 0

-b+or - the square root of b^2-4ac
_______________________________
2a

2006-07-27 15:01:23 · answer #9 · answered by soccerqueen155 2 · 0 0

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