how to find horizontal asymptote of 1) y= x/ sqrt of x^2 -4?

Question

2) y= x^3/ sqrt ofx^2 -9
3) x^2y =9
Find the vertical and horizontal asymptote for
4)x-1/(x^3 -6x^2+ 11x-6)
5) 2x^2 / sqrt of x^4 +25
6) y= x-3 / sqrt of x^2 -6x+9
show the steps please

Answer 1

Horizontal asymptote: take the limit of x as it approaches +/- infinity

Answer 2

Are you saying the sq. root of x^2? That would be x. Simplify the problems first. If that is indeed what the problem says, problem #1 would then become x/x -4 which is 1-4 = -3. That's a horizontal line. Is that really what the problem says?