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(Assume any veriables in the expression are nonzero.)

(t^3)^ -1/2(3t^3)

2006-07-27 13:47:56 · 4 answers · asked by Brain 3 in Science & Mathematics Mathematics

this is not a divison question. Let me try to rewrite it.

(t^3) ^ (-1/2) (3t^3)

It is all in one straight line.

2006-07-27 13:58:11 · update #1

4 answers

if by this you mean

((t^3)^(-1/2)) * (3t^3)
(1/(t^(3)^(1/2))) * (3t^3)
(3t^3)/(t^(3 * (1/2)))
(3t^3)/(t^(3/2))
3 * t^(3 - (3/2))
3 * t^((6/2) - (3/2))
3 * t^((6 - 3)/2)
3 * t^(3/2)
3t^(3/2)

2006-07-27 14:45:41 · answer #1 · answered by Sherman81 6 · 0 0

Tough to say without knowing if the fraction line divides the whole problem so the 2(3t^3) is all on the bottom, or not.

If it does, the top is t^-3 (multiply the exponents); then subtract the exponents to get 1/6t^-6 which equals t^6 all over 6

2006-07-27 20:55:42 · answer #2 · answered by hayharbr 7 · 0 0

First of all, I don't fully understand your notation there. You need proper use of brackets or else your question becomes ambiguous. Regardless, I'll show you how to do it:

When a variable has a negative exponent, that means it is in the denominator instead of the numerator. x^(-1) is the same as 1/x. This is also how you change your exponents to positive. If you have t^(-3) then by putting it in the denominator you remove the negative giving you 1/(t^3). The same is true for a negative exponent in the denominator, you would just move it to the numerator to remove the negative.

Hope this helps.

2006-07-27 20:55:30 · answer #3 · answered by CubicMoo 2 · 0 0

(t^3)^ -1/2(3t^3) i never seen any equation like this!

do you mean (t^3) -1/2(3t^3) ?

2006-07-27 20:56:44 · answer #4 · answered by ___ 4 · 0 0

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