2006-07-27 12:00:12 · 7 answers · asked by missmia386 1 in Science & Mathematics ➔ Mathematics
(1/3)^X=12
log{(1/3)^X} =log(12)
X * log(1/3) = log(12)
X * -log(3) = log(12)
X = -log(12)/log(3) = -2.26
Th
2006-07-27 12:05:21 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋
First, realize that (1/3)^X will yield a negative exponent. Once you see this, you can convert this into the equivalent 3^-X where -X is a positive number.
Now you just solve 3 to some exponent equals 12 and whatever the answer is, multiply by -1.
You can also multiply (log 12) / (log 3) by minus 1.
2006-07-27 20:24:48 · answer #2 · answered by aichip_mark2 3 · 0⤊ 0⤋
Tank Natural Log both sides
x * Ln (1/3) = Ln 12
Divide bothe sides by Ln(1/3)
x = Ln(12)/Ln(1/3)
x = 2.26185
2006-07-27 19:08:48 · answer #3 · answered by f21ck 3 · 0⤊ 0⤋
x * log 1/3 = log 12
2 2
x*log 1/3 = log 4 + log 3
2 2 2
x * log 3 = -(2 + log 3)
2 2
x= -2/log 3 -1
2
2006-07-27 19:04:02 · answer #4 · answered by Roxi 4 · 0⤊ 0⤋
(1/3)^x = 12
log(1/3)12 = x
x = (log(12))/(log(1/3))
x = about -2.26185951
2006-07-27 19:42:05 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
(1/3)^x = 12
taking log on both the sides
log(1/3)^x = log12
xlog(1/3) = log12
x(log1 - log3) = log12
x(0 - log3) = log12
-xlog3 = log12
x = -log12/log3 = -log(12-3) -log9
x = -log9
2006-07-27 23:47:04 · answer #6 · answered by Subhash G 2 · 0⤊ 0⤋
(1 / 3)^x = 12
[(3)^(-1)]^(x) = 12
(3)^(-x) = 12
-x = log3 [12]
x = -log3 [12] = -ln(12) / ln(3) = approx. -2.26186
2006-07-27 19:14:17 · answer #7 · answered by Louise 5 · 0⤊ 0⤋