a bag contains 12 marbles, one marble is drawn, the probability of drawing a blue marble is 1/3,?

Question

the probability of drawing a red or blue marble is 1/2, how many of the marbles are red?
six red, 4 blue, 2 white chips are in a box, find the odds of choosing a blue chip from the box?
refer to the question just asked, find the odds of choosing a red or white chip? automatic 10 points

Answer 1

There are 2 red marbles (1/3 of them are blue = 4, 1/2 of them are either red or blue = 6; 6 - 4 = 2)

Chance of chosing a blue chip = 4/12 = 1/3; chance of chosing red OR white (i.e. NOT blue) = 1 - 1/3 = 2/3

Answer 2

1) there are 2 red marbles

explanation: if a third of the marbles are blue then that means there are 4 blue marbles...and if the probability of drawing a red/blue marble is a half then that means there are 6 red and blue..
therefore, there are 2 red marbles

2)odds of choosing a blue chip = 4/12 = 1/3
odds of choosing a red or white = 8/12 = 2/3 (or u can say 1- 1/3 = 2/3)

explanation: there are a total of 12 marbles (6 red, 4 blue, 2 white) so choosing a blue would be 4 over the total (12) which is a third and choosing a red/white will be the rest (1- 1/3) cuz there are no other colours

hope it helps ;)

Answer 3

(i) Since the probability of drawing a blue marble is 1/3 there must be 4 blue marbles.The probability of drawing a red or blue marble is 1/2, so there are a total of six blue and red marbles. Subtracting the 4 blue marbles shows that there are 2 red marbles in the bag.
(ii) There are 4 blue chips out of a total of 12 chips in the box, so the probability of choosing a blue chip is 1/3 and thus the odds are 1 to 2. There is a total of 8 red and white chips, so the probability of choosing one of those is 8/12 = 2/3 and the odds are 2 to 1.

Answer 4

The question contains a contradiction. If the probability of red or blue is 1/2 and the probability of blue is 1/3 and we are given there are 12 marbles, then from this we can deduce that there are 4 blue marbles and 2 red marbles. Contradiction arises when you say there are 6 red marbles - this is not possible. Make sure you provided the correct question.

Answer 5

for the first question, 1/3 *12 = 4 blue marble
4 +x = 1/2 * 12 = 6
x = 2 red marbles

for the second question, total number of chips = 6 +4 +2 = 12
odds of blue = 4/12 = 1/3 or 33.333%

red "or " white means probability of red + probability of white
red or white = 6/12 +2/12 = 8/12
8/12 = 2/3 or 66.67%

Answer 6

If this is the first drawing: (Twelve marbles)... 1 out of 12 as the marble selection decreases, the odds will increase for picking a blue if they were not picked from the previous pickings.

Your statements are run-ons and hard to decipher where one puzzle starts and the other finishes.

In reference, to the chips there are red and white chips. There's a 50/50 chance of picking either color. Are there blue chips in the box?

Answer 7

2 red marbles,
the odds are 1/3 for blue
odds are 1/2 for red and white

Answer 8

1/3 of 12 = 4 so there are 4 blue
1/2 of 12 = 6 so there are 6 that are blue or red, since there are 4 blue, then there must be 2 red

12 chips total and 4 are blue. Odds refers to the number of times something can happen to the number of times it can't. So 4 chips are blue, 8 chips are not blue, the odds are 4:8 which can be reduced to 1:2.

There are 8 red or white ; there are 4 that are not red or white (because they're blue); so the odds are 8:4 reduced to 2:1

PLEASE BE CAREFUL OF PREVIOUS ANSWERS THAT ARE GIVING YOU PROBABILITY FOR YOUR SECOND AND THIRD QUESTION AND NOT ODDS

Answer 9

2
1/3
1/2
1/6

Answer 10

1/2 chance of choosing red and 1/6 chance of choosing white and there are 3 red marbles and a 1/3 chance of choosing a blue marble


mensa is wrong, trust me i no im in honors calc