help!!!!!!!!!!?

Question

simplify:

#1. (c-2) 3c+6 / c^2-4


#2. (b-3) b^2-3b-18 / b^2-9

#3. (4a-2 / a^2 +3a)(a^2-a-20/2a^2+7a-4)

#4. [(4x^5)(y^2) / (x^2-9)](x^2+5x+6 / (8x^2)y

Answer 1

Hmmmmmmmmmmmmm. OH HOME WORK HELP LINE.

Answer 2

#3. You seem to have left out some parentheses. My guess is that you should have written

[(4a - 2)/(a^2 + 3a)][(a^2 - a - 20)/(2a^2 + 7a - 4)]

Completely factor each numerator and denominator

4a - 2 = 2(2a - 1)
a^2 + 3a = a(a + 3)
a^2 - a - 20 = (a - 5)(a + 4)
2a^2 + 7a - 4 = (2a - 1)(a + 4)

I end up with

[2(a - 5)]/[a(a + 3)]

or

(2a - 10)/(a^2 + 3a)

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#4. [(4x^5)(y^2) / (x^2-9)](x^2+5x+6 )/ (8x^2)y

I added a right parenthesis above.

x^ - 9 = (x + 3)(x - 3)
x^2 + 5x + 6 = (x + 2)(x + 3)

After cancelling

4x^3y(x + 2)/(x - 3)

Answer 3

This is what my friend got-she is going to be a highschool math teacher and is really really good at math-hope this helps
"Here's what I can best figure out considering the arrangement of the parentheses from the original problems....A"

#1. 3
#2. b-6
#3. (2(a-5))/(a(a+3)) or 2a-10/a^2+3a (Same thing - just factored out)
#4. ((x^4y+2x^3y)/(x-3)

Answer 4

That's why i dislike math, it's supposed to just be numbers... they lost me when they started putting letters in the equations....

Answer 5

Yeah! Nice try, hon! You can't pay me enough to do your homework!

Answer 6

dude, u had me at hello

Answer 7

I dunno why we learn this in school anyway, cause later on we forget all about it, just like me!

Answer 8

sorry BUT i ain't gonna help ya do ur homework!!!!!!!!!!!

Answer 9

i am not einstein!