Problem 2.
Find the product of the complex number and it's conjugate:
(4-6i)
2006-07-27 06:37:15 · 6 answers · asked by Brandon ツ 3 in Science & Mathematics ➔ Mathematics
(sqrt(2))/(sqrt(18))
(sqrt(2))/(sqrt(9 * 2))
(sqrt(2))/(3sqrt(2))
ANS : 1/3
(4 - 6i)(4 + 6i)
16 - 36i^2
16 - 36(-1)
16 + 36
52
2006-07-27 14:40:00 · answer #1 · answered by Sherman81 6 · 2⤊ 0⤋
50
2006-07-27 06:43:17 · answer #2 · answered by seba 1 · 0⤊ 0⤋
1: 1/3
2: = (4-6i)(4+6i) = (16 +36) = 52
2006-07-27 06:43:00 · answer #3 · answered by ConradD 2 · 0⤊ 0⤋
root 18 can be written as (root 2 *root 9). so the root 2s on the numerator and denominator can be cancelled out.
that leaves 1/root 9
that's equal to 1 / 3
see i am a genius!!!
2006-07-27 10:01:58 · answer #4 · answered by teenwitch 2 · 0⤊ 0⤋
sqrt(2)/sqrt(18)
is
sqrt(2)/sqrt(2*3*3)
or
sqrt(2) / (3 * sqrt(2))
which reduced upon division to
1 / (3 * 1)
or
1/3
2006-07-27 06:42:35 · answer #5 · answered by Curly 6 · 0⤊ 0⤋
sqrt2/sqrt18 = sqrt2/18 = sqrt1/9 = 1/3
2006-07-27 18:37:02 · answer #6 · answered by Subhash G 2 · 0⤊ 0⤋