Rationalize the expression with a rational denominator:?

Question

7/√3

Problem 2:

Rewrite in simplified radical form:

√30/√5

Look at my record, I will select a best answer asap(-:

Answer 1

7/(sqrt(3))
(7sqrt(3))/3

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(sqrt(30))/(sqrt(5))
(sqrt(150))/5
(sqrt(25 * 6))/5
(5sqrt(6))/5
sqrt(6)

Answer 2

What times √3 gives you a rational number? √3
, that's what, because √3√3 = 3 by definition of square root. So multiply both numerator and denominator by √3. The result is 7√3/3 or (7/3)√3
or (√147)/3.

The second problem can be done the same way, but maybe it's better to divide 30 by 5 and get 6. Answer √6.

Answer 3

sqrt(4) = 2 sqrt(4)/sqrt(6) = 2/sqrt(6) Now multiply the precise and backside via sqrt(6). 2/sqrt(6) = 2sqrt(6)/6 Now cut back 2/6 to a million/3 answer: sqrt(6)/3 (4-3i)-(8-2i) First distribute the unfavourable sign = 4 - 3i - 8 + 2i Now combine like words = -4 - i

Answer 4

Not sure what you mean by the first problem

7/sqrt(3)

but if you multiply the numerator and denominator by sqrt(3) you get

7sqrt(3)/3

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sqrt(30)sqrt(5) = sqrt(6*5)sqrt(5) = sqrt(6)sqrt(5)sqrt(5) = sqrt(6)*5 = 5sqrt(6)

Answer 5

i'm sick of these math questions. do your own sh*t