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In a carpark , the ratio of red cars to green cars is 5 :6 while the ratio of green cars to blue cars is 3:10 .Find the ratio of red cars to blue cars.

Sol.
Red : Green : Blue
5 : 6
3 : 10

Or 15 : 18 : 60

Or 5 : 6 : 20

Therefore ratio of Red cars to Blue cars is


5 : 20 or 1 : 4

2006-07-27 03:52:11 · 10 answers · asked by sara_82 1 in Science & Mathematics Mathematics

10 answers

Red: Green = 5:6
Green: Blue = 3: 10

To get a common ratio for all the 3 objects
you need to get the comman object(green) have the same ratio value in both the equation
For this you need to take the LCM of the ratio values of green ie 6 and 3
the LCM of 6 and 3 is 6 itself
So to get 6 in the first equation
you need to multiply it by 1
ie 5*1 : 6*1 Here for the ratio to remain the same you need to multiply 5*1
ie 5:6

Now in the second equation green is 3
to get 6 multiply it by 2
ie 3*2:10*2 Here for the ratio to remain the same you need to multiply 10*2
the equation becomes
6:20
Now since the equations have a comman value of green they can be put together

ie 5:6:20

Now since they are in order we can take the ratio of Red and Blue directly
ie 5:20
Which when simplified is
1:4

I hope now you can teach your lil sis, how to solve the problem

2006-07-27 04:10:30 · answer #1 · answered by tuhinrao 3 · 0 0

Start with 5 Red cars and 6 Green cars.

There are 10 Blue cars for every 3 Green cars, so for 6 Green cars there will be 20 Blue cars.

So now you have 5 Red cars and 20 Blue cars.

The ratio is the smallest representation you can find.

Divide the Blue cars by the Red cars to get 4. This way the first number in the ratio will be 1 and the second will be the result of the division.

1:4

This example shows whole numbers.

2006-07-27 04:03:48 · answer #2 · answered by JeffE 6 · 0 0

For every 5 red cars there are 6 green cars.
For every 3 green cars there are 10 blue cars, so for 6 green cars, there must be 20 blue cars. You have now established that for 6 green cars there are 5 red cars and 20 blue cars, so the ratio of red to blue is 5:20, or 1:4.

Is this what you were asking?

2006-07-27 04:00:38 · answer #3 · answered by Graham I 6 · 0 0

for every 3 green cars there are 10 blue cars
so its 15:18:60
U can have ratios with three figures this till works and gives u the ratio of the three colours of car. U can work out this sum by cancelling down to get 5:6:20 and red and blue is 5:20

2006-07-27 19:49:10 · answer #4 · answered by motown 5 · 0 0

Since the ratio of red cars to green cars is 5:6 and the ratio of green to blue cars is 3:10 divide the 6 by two. this is because you get 3 which is equal to 10 blue cars. since you divided the 6 by two you must also divide the 5 by two which is 2.5. now you have 2.5:10. this equals 1:4.

2006-07-27 04:17:20 · answer #5 · answered by highschoolmusicalfan 3 · 0 0

il try to explain in lay terms

Since thr ratio of red to green cars is 5:6, for evey 5 red cars there are 6 green cars and vive versa. now in case of g to blue is 3:10 ie for every 3 green cars there 10 blue ones and vice versa. now let there be 6 green cars(coz green is the common color in both ratios) in all(just to explain in the simplest ratio). then as per the red green ratio, there will be 5 red cars, and again frm the grn blue eqn, there are 10*2(3/10*2/2) or 20 blue cars. now we have:

5 red cars six green ones and 20 blue ones so, the ratio of red blue becomes 5:20 or 1:4

2006-07-27 04:03:32 · answer #6 · answered by Anonymous · 0 0

red:green = 5:6(2)

...which means every 5 red car has 6 green cars...but this doesnt mean there r only 5 red cars present...there could be more. but in the question we are not concerned about the real number.

moreover, green:blue = 3:10 (2)

forever 3 green cars there r 10 blue cars.
to compare the eqation...lets consider green cars which r common

lets multiply eqn (2) by 2 to get the comparison
implies green:blue= 6:20

now we get,
green:red:blue = 6:5:20

considering only red and blue
red:blue=5;20
= 1:4

ratio doesnt deal witht he real numbers...just gives an idea of proportion in which different cars are present.

2006-07-27 05:30:57 · answer #7 · answered by aqua456 2 · 0 0

The only thing that connects red to blue is green. Therefore, they need to be equally related to green in order to make a comparison. In the above problem, you only need to multiply the second term by two, or divide the first term by two. Once red and blue are compared to an equal number or green you will know the ratio to each other.

2006-07-27 04:06:33 · answer #8 · answered by dave 2 · 0 0

Red: Green
5:6
Blue:Green
10:3

So, for every 3 green cars you have you have 10 blue cars, so for every 6 (3x2)green cars you have 20 blue cars (10x2). For every 6 green cars you also have 5 red cars so the rationof red:blue is 5:20

Hope this helps

2006-07-27 04:33:43 · answer #9 · answered by rachael p 2 · 0 0

Sara, i must admit you don't really need any help...your solution and method are impeccable please stick by them. In fact what you've done is proportioned the weights of the three colours of car by placing their three ratios next to each other. Relative probability is used in the two separate ratios and so the absolute ratios are found by placing them side by side, weighting them as you do.....Great work, hardly any help needed though!

XX

2006-07-27 04:09:57 · answer #10 · answered by RobLough 3 · 0 0

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