Mary has a school project – a fund raising program. She has to sell 20 tickets , 2 of a kind the Php100 & Php

Question

Mary has a school project – a fund raising program. She has to sell 20 tickets , 2 of a kind the Php100 & Php200 tickets. She sold all the tickets and earned Php 2,500.00, but she forgot how many pcs of Php100 & Php200 tickets she has.

Answer 1

She sold 20 tickets.

Let x = number of Php100 tickets.
So 20-x = number of Php200 tickets.

100x + 200(20-x) = 2500
100x +4000 - 200x = 2500
1500 = 100x
x = 15

She sold 15 at Php100 (for 1500) and 5 at Php200 (for 1000).

Answer 2

Let x be Number of Php100 tickets,
and y be Number of Php200 tickets.

100x + 200y = 2500 ....(Equation 1)
x + y = 20 ...................(Equation 2)

Multiply Equation 2 by 100,

100x + 100y = 2000 ...(Equation 3)

Subtract Eqn 3 from Eqn 1 (eliminating the x)

100y = 500
y = 500 / 100
y = 5

Substitute y =5 into Eqn 2

x + 5 = 20
x = 20 - 5
x = 15

Therefore : She had 15 Php100 tickets &
5 Php200 tickets.

Got it ?

Answer 3

Let
x = number of P 100 tickets
y = number of P 200 tickets
x + y = 20

.·.
100x = total cost of P 100 tickets
200y = total cost of P 200 tickets
100x + 200y = 2500
Simplify:
x + 2y = 25

You now have the following equations:
x + 2y = 25
x + y = 20

Subtract the 2nd eq. from the 1st eq.
y = 5

Thus,
x + 5 = 20
x = 15

.·.
Mary had 15 pieces of P 100 tickets and 5 pieces of P 200 tickets.

^_^

Answer 4

Mary sold 15 pcs of Php100 & 5 pcs of Php200

Solution..

I. 100x php+ 200y php= 2500 php
II. x php + y php = 20 php

Solving for x and y we get x as 15 and y as 5.

Answer 5

You should try this on your own.

It is simple.

Let us assume that she sold x tickets worth Php100
and y be tickets worth Php200

so x + y = _____ (total no of tickets)

and 100 * x + 200 * y = ______ (total earnings).

I hope this helps. Do let me know if you need more help. But try and solve this on your own.

Answer 6

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Answer 7

15 of php100
5 of php200