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i think you can, but im not sure.

2006-07-26 21:27:23 · 10 answers · asked by mmeerrrrrrr 1 in Education & Reference Homework Help

10 answers

Yes, you can. For example, the cube root of (-8) is (-2), because
(-2)*(-2)*(-2) = -8.

2006-07-26 21:29:38 · answer #1 · answered by green egg 2 · 0 0

Yes, because you can multiply 3 same (negative) numbers to get a negative number, therefore, it is possible to take a cube root of negative numbers. But with a square root, you can't because you cannot multiply two same numbers to get a negative answer. Hope this helps ^ _ ^

2006-07-27 06:52:57 · answer #2 · answered by Black Shadow 1 · 0 0

yeah u can. the cube root of a negative no is also a negative number. example. the cube root of -27 is -3.

2006-07-27 04:30:24 · answer #3 · answered by skuxyliliex 3 · 0 0

Yes you can have the Nth root of a negative number.

if N is even like 2, i.e. square root. the result is in form of a imaginary number "i" as sqrt(-1) =1

but if N is a odd number, like 3, i.e. cube root the result is a negative number as (-1)^(1/3) = -1

for any negative number, -x factor it as: (-1)*x
and that'll help you in the understanding

2006-07-27 05:00:19 · answer #4 · answered by Avik S 2 · 0 0

Yes you can. the cube root of -27 is -3. Check that with your calculator if you don't believe me.

2006-07-27 04:30:40 · answer #5 · answered by cyanne2ak 7 · 0 0

yes u can.

eg: -2 * -2 * -2 = -8

i.e. cube root of -8 is -2. always the cube root of -ve number is -ve.
in maths when u multiply 2 -ve numbers u get a +ve ans. when u do multiply 3 -ve numbers u get a -ve ans.

2006-07-27 05:38:53 · answer #6 · answered by the brillant once! 2 · 0 0

Yes, cubes are possible. Squares however result in imaginary numbers.

2006-07-27 04:30:42 · answer #7 · answered by Anonymous · 0 0

Yes.

2006-07-27 04:54:51 · answer #8 · answered by Whatever 3 · 0 0

Yes, of course! you can

2006-07-27 04:31:33 · answer #9 · answered by fsanchez75 2 · 0 0

yes, you can

2006-07-27 06:58:34 · answer #10 · answered by geoff_khu 1 · 0 0

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