1) divide both sides by 5 so that you isolate x on the left side of the equation
2) You have to distribute the exponent outside the parentheses. To do this, multiply the exponent on the x (2) by the exponent outside the parentheses (2). Do the same for the exponent on the y (4).
2006-07-26 18:31:34
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answer #1
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answered by jimbob 6
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1) This is impossible. You only have one equation with two variables. If you want to solve for one of these, you need at least one more equation containing those variables. Rule of thumb:
(# of variables) < or = (# of equations)
then you can solve it
2) If you raise x^2 to the second power and y^4 to the second power as well, you just follow the power rule and multiply the exponents.
Product rule:
((x^a)^b) = x^(a*b)
So x^2 would become x^4 and y^4 would become y^8.
I'm unclear as to whether or not the (-1/2) is squared as well, if it were you'd get 1/4, which is just (-1/2) times (-1/2).
I hope this helps.
(^ means to the power of)
2006-07-27 00:30:07
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answer #2
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answered by CubicMoo 2
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1 is just divide it by 5!
so
5x=y
_______
5
and the 5 cancel out so u have y over 5
2
(-1/2) (x^2y^4)^2 Parentacy first then powers so 2 times 2 and 2 times 4 for the powers! I hope this helps! Writing is easier! typing dont work well! if u need math help im here! and im asian so.... email me
2006-07-27 00:43:41
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answer #3
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answered by vaiosoft 4
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1. In this equation you want X on one side and everything else on the other side. You can do this by deviding BS (both sides) by 5.
2. -.5X^2*Y^4
Here you can put the X and Y in brackets and change the power (exponent), 2 becomes 1 and 4 becomes 2 with the brackets raised to the power of two.
Hope this makes sense.
2006-07-27 02:25:01
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answer #4
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answered by bullswool888 5
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1. just divide both sides by five, when solving for x, isolate x on one side of the equation.
2. square what is inside and make the top negative, so -x4y8 all over 2
Hope that helps.
2006-07-27 00:27:15
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answer #5
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answered by keats27 4
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5x = y ;
firstly the value u want to find out should be in one side and the value's u have already have in one side, in this case u will place x alone and the rest of the values the other side..
so it will be
x = y/5;
when u shift variables or integers from one side to other it has certain rules...
if the value is + then when u shift it becomes -, or
if the value is - then when u shift it becomes +, or
if the value is * then when u shift it becomes /, or
if the value is / then when u shift it becomes *;
2006-07-27 01:00:58
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answer #6
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answered by fzaa3's lover 4
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well i only know the first
u have to multiply each side by 1/5
2006-07-27 09:47:49
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answer #7
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answered by somebody 2
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undo the order of operations. If you know PEMDAS, then start at the back.
If you have subtraction, then add.
If you have addition, then subtract.
If you have division, then multiply.
If you have multiplication, then divide.
If you have exponents, then undo the exponent by taking the root.
Those are the directions.
2006-07-27 00:25:53
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answer #8
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answered by powhound 7
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divide y by 5
and umm....
2006-07-27 00:25:47
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answer #9
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answered by Anonymous
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