2006-07-26 14:26:43 · 6 answers · asked by needalgebrahelp 1 in Education & Reference ➔ Homework Help
a>0
2006-07-26 16:33:34 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
a>-2
2006-07-26 21:30:54 · answer #2 · answered by raymonde32132 1 · 0⤊ 0⤋
treat like an equation
a+2 > 0 subtract 2 from both sides
a > -2
Solution set = { a | a > -2 }
written out "The solution set is a such that a is greater then -2"
2006-07-26 21:33:16 · answer #3 · answered by math guru 4 · 0⤊ 0⤋
a/ (a+2) > 0
multiply both sides by (a+2)
(a+2)a / (a+2) >0 (a+2)
since 0(a+2)=0
then (a+2)a / (a+2) > 0
since (a+2)/(a+2) = 1
then (a+2)a / (a+2) = a
therefore a > 0
2006-07-26 23:56:20 · answer #4 · answered by average joe 1 · 0⤊ 0⤋
i'm a little confused on the wording of your question so here are both of my takes on your problem:
if it says a/a+2 >0 then:
a+2(a/a+2)> 0 (a+2)=
A>0
or if it is a+2 > 0
a+2-2> 0-2=
a>-2
hope i helped you out!!
2006-07-26 21:40:58 · answer #5 · answered by Charly P 2 · 0⤊ 0⤋
a> -2 idk what you mean...
2006-07-26 21:30:36 · answer #6 · answered by Michael J with wings 3 · 0⤊ 0⤋