How many more square feet of tile would it take to cover a cube of side 8' than a sphere of diameter 8'?
2006-07-26 13:15:43 · 6 answers · asked by laqitta 1 in Science & Mathematics ➔ Mathematics
The surface area of the square equals 8x8x6 or 384"
The surface area of a sphere equals 4*pi*r2 or
4*3.14*16 which equals 200.94"
384-200.94= 183.04" more to cover the cube than the sphere
2006-07-26 13:22:48 · answer #1 · answered by cjmacri 3 · 2⤊ 1⤋
Circle: surface area = 4*pi*r*r=4*3.14*(8/2)*(8/2)=201 sqft
Cube: surface area=6*L*L=6*8*8=384 sqft
How many more square feet of tile would it take to cover a cube of side 8' than a sphere of diameter 8'? 384-201=182.9 sqft.
2006-07-26 20:24:48 · answer #2 · answered by Joe 2 · 0⤊ 0⤋
I will give you the formula for the surface area of a sphere and surface area of cube and you can do the rest.
The surface area of a sphere is 4 Pi r^2 where r is the radius of the sphere.
The surface area of a cube is 6 l^2 where l is the length of one side.
Work the numbers with a calculator and you will have your answer.
2006-07-26 20:25:58 · answer #3 · answered by rscanner 6 · 0⤊ 0⤋
Area of cube = 8 x 8 x 6 = 384 sq ft.
Area of sphere = 4 x PI x r^2 = 4 (3.1415926) (4^2)
= 201.0619264 sq ft.
Difference = 384 - 201.0619264 sq ft
= 182.9380736 sq ft.
2006-07-26 20:57:21 · answer #4 · answered by ideaquest 7 · 0⤊ 0⤋
Find the square feet of both and then subtract to find difference
Cube surface area = s^3 = 8^3 = 512
Sphere surface area = 4*pi*r^2 = 4*4^2*pi = 64 * pi = 200.96
512-200.96 = 311.04
2006-07-26 20:23:05 · answer #5 · answered by math guru 4 · 0⤊ 0⤋
find the diff of surface area:
use the formula..
surface area of cube= 6*side^2
surface arae of sphere= 4*pi*r^2
2006-07-26 20:24:20 · answer #6 · answered by Vivek 4 · 0⤊ 0⤋