gas has volume of o.20 cubic meters and absolute temperature of 333 kelvin , if the temp. is raised to 533 wha

Question

what is the new volume of the gas ? assume that theres no change in pressure

Answer 1

U must use the General Gas Equation for Gasous State:
(P1*V1)/T1 = (P2*V2)/T2
Since pressure didn't change, therfore the equation will be:
V1/T1 = V2/T2
0.20/333 = V2/533
therfore V2 = (0.20/333)*533
V2 = 0.32 cubic meter

i hope u got ur point from my explanation

Answer 2

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Answer 3

PV = nRT or P/nR = T/V

P x .2 = n x R x 333 or P/nR = 333/.2 = 1665

n, R, and P remain the same so the new volume should be

1665 = 533/V or V = 533/1665 which is about .32 m^3

Answer 4

use the PV over T equation as pressure does not change it is
V1/T1 = V2/T2
which is o.20/333 = V2/533
so to work it out u do (0.20/333)*533 = V2
i find it helps if u know the equation as well as the answer.. answer is like 0.32 m (cubed) to 2 decimal places.

Answer 5

PV(a million)=nRT(a million) PV(2)=nRT(2) Divide equation 2 with suggestions from equation a million, and also you get: V(2)/V(a million)=T(2)/T(a million) sparkling up for V(2), which equals T(2)V(a million)/T(a million), that may be: 533 ok * 0.20 m3 / 333 ok it really is 0.32 m3.

Answer 6

0.2 X 533 / 333

Answer 7

T1V1=T2V2
because pv=nrt
P, N and r are constant
plug and chug my dear

Answer 8

0.32012 m^3