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i need to know for probability math problem.

2006-07-26 11:38:02 · 9 answers · asked by Lorrane 2 in Education & Reference Homework Help

9 answers

In a standard deck, there are four suits -- heart, diamonds, clubs, and spades.
There are 13 cards in each suit - ace, two, three, four, five, six, seven, eight, nine, ten, jack, queen, and king.
In some decks there are also two joker or wild cards.

Hope this helps!

2006-07-26 11:43:53 · answer #1 · answered by Barney's Betty 2 · 0 0

A deck has 52 cards divided into 4 suits: spades, diamonds, clubs, and hearts. Each suit is made up of a 2, 3, 4, 5, 6, 7, 8, 9, 10, ,jack, queen, king, ace.

2006-07-26 18:48:27 · answer #2 · answered by x 5 · 0 0

1 Deck
4 suits
each suit has 13 cards:
Ace, King, Queen, Jack, 10 9 8 7 6 5 4 3 2

52 cards in a deck

2006-07-26 18:42:05 · answer #3 · answered by Anonymous · 0 0

There are 13 of each suit:
2,3,4,5,6,7,8,9,10, Jack, Queen, King, Ace

There are 4 suits each having the 13 values mentioned above: Spades, Hearts, Clubs, Diamonds.

13 * 4 = 52

That makes 52 playing cards total

Most decks also have a least one Joker (which most games do not use)

2006-07-26 18:43:31 · answer #4 · answered by David D 4 · 0 0

There are four suits: hearts, clubs, spades, and diamonds.
There are 13 cards within each suit: Ace, King, Queen, Jack, Ten, Nine, Eight, Seven, Six, Five, Four, Three, and Two.
There are a total of 52 cards.
Two of the suits (hearts and diamonds) are red: Total = 26
Two of the suits (clubs and spades) are black: Total = 26

2006-07-26 18:52:29 · answer #5 · answered by PuttPutt 6 · 0 0

the suits in a deck of playing cards are hearts clubs spades and diamonds so 4

2006-07-26 18:42:01 · answer #6 · answered by treylynnllewelyn 2 · 0 0

4 suits - Hearts, Spades, Clubs, Diamonds

2006-07-26 18:43:51 · answer #7 · answered by Anonymous · 0 0

Hearts,Spades,Clubs,Diamonds,and 4 of each a total of 52

2006-07-26 18:41:06 · answer #8 · answered by Anonymous · 0 0

four suits, clubs, diamond, spades,heart.. for of each number and letter

2006-07-26 18:42:37 · answer #9 · answered by uniqueniky 2 · 0 0

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