that's x-a times x-b up to x-z...
2006-07-26 10:19:00 · 5 answers · asked by hapie_09 1 in Science & Mathematics ➔ Mathematics
By solving, you first have to have an equation.
Assume the equation is (x-a)(x-b)...(x-z)=0, then the answer is simple: the problem has 26 roots, a, b, c, ...
The logic behind the solution is, if the product of N numbers is 0, at least one of the number has to be 0.
You have to assume that x here is just a dummy varibale, i.e., it can be replaced by, for example, "X", "Y", or anything not one of the 26 alphabets to avoid confustions.
2006-07-26 10:26:38 · answer #1 · answered by Stanyan 3 · 0⤊ 1⤋
0
2016-06-13 21:12:29 · answer #2 · answered by Priya 1 · 0⤊ 0⤋
I believe it's 0 because (x-x) = 0
2006-07-26 10:31:57 · answer #3 · answered by Gynolotrimena Lubriderma-Smith 3 · 0⤊ 0⤋
it is zero because one of the terms is x-x or 0
2006-07-26 12:13:39 · answer #4 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
Technically, that expression will be zero...
because it contains (x - x), which is always zero.
2006-07-26 10:26:31 · answer #5 · answered by dutch_prof 4 · 0⤊ 0⤋