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All of the above answers are either wrong, aren't answers, or don't follow the instructions by not using the quadratic formula.

Quadratic formula:
(-B + or - square-root(B^2- 4AC))/2A
So...
(-2+ or - sqrt(4-(-96)))/2
(-2+ or - sqrt(100))/2
(-2 +or- 10)/2
Now branch it out. First lets solve it with the +:
(-2 + 10)/2 = 4
Now the -:
(-2 - 10)/2 = -6
The two solutions are:
x = 4
x = -6

I hope this helps, and wish you all the best!

2006-07-26 09:02:56 · answer #1 · answered by Dan 4 · 0 0

Because the factors for 24 are 1 and 24, 3 and 8, 4 and 6 and the only ones that make a possible sum/difference of 2 are 6 and 4 so the equation must use these two numbers. Since 24 is negative, this means that one of the factors is negative. This means that 2 is derived from a subtractive formula and since it is positive, this means that the positive factor is greater than the negative factor. So, you can infer that (6)(-4) = -24 and 6 - 4 = 2.

X^2 + 2x - 24 = 0 can be factored out into
(x + 6)(x - 4) = 0

When the product of multiplication is 0, this means that one of the multiplicants must be 0. So you set this equation:

x + 6 = 0 or x - 4 = 0
x = -6 or x = 4

So, the solution for x^2 + 2x - 4 = -6, 4.

The quadratic formula that is mentioned:

x = [-b+/-sqrt(b^2-4ac)]/2a

is used when the quadratic equation can not be factored out. It is more involved calculation and when the equation can be factored out, it's easier to just solve by factoring. You can also graph this equation to solve it.

2006-07-26 16:35:46 · answer #2 · answered by Esh F 2 · 0 0

x^2 +2x-24=0
quadratic formula = -b (plus or minus) sqroot(b^2-4ac) divided by 2a

a=1 (1x^2), b=2 (2x), c=-24 These are the coefficients of the formula. Plug these in to the equation, and you get an answer.
Look at http://www.purplemath.com/modules/quadform.htm for more help. It is kinda hard to show the quadratic equation by typing it.
you can do it by the other suggested ways, but were'nt you aksed to solve it with the quadratic equation?

2006-07-26 15:58:10 · answer #3 · answered by tim mcdonald 1 · 0 0

Here is Quadratic Formula
x= ( - b (+ or -) squa root ( b^2 -4ac) ) / 2a
a = 1, b = 2, c = -24
x= ( -1 (+ or -) Squa root ( 4 - ( 4*1* -24)) ) / 2
x= (-2 ( + or - ) 10) / 2
So x = -6 or 4
All right>)

2006-07-26 16:05:00 · answer #4 · answered by Hsu Thet H 2 · 0 0

The quadratic formula is (-b +/- sqrt(b^2 - 4*a*c))/2a, where sqrt means square root; +/- means plus or minus, and you have to do it both ways to get both solutions; and a, b and c are the co-efficient of x^2, that of x, and the constant term: in this case, a=1, b=2, and c=-24.

Work the rest out yourself.

2006-07-26 15:58:43 · answer #5 · answered by Anonymous · 0 0

(x+6)(x-4) = 0

2006-07-26 15:56:30 · answer #6 · answered by gimli_1977 3 · 0 0

find the factors of -24 that when added together equals +2. It is called the AC method as in Ax^2 +Bx - C = 0.
Shame on all those who did it for you instead of telling you how to do it.

2006-07-26 16:13:08 · answer #7 · answered by Caffeinated 4 · 0 0

well, find something that multiplies eachother to = - 24.
those two numbers MUST add up to +2
therefore, 6 x -4 = -24, and 6+ (-4) = 2
yay! so:

(x + 6)(x - 4) = 0

x = -6,or x = 4

tada~~

2006-07-26 15:57:03 · answer #8 · answered by sasmallworld 6 · 0 0

I'm not sure that this is what you want, but here goes:

(x + 6)(x - 4) = 0

Hope this helps !

2006-07-26 15:56:34 · answer #9 · answered by dragoneye_2005 1 · 0 0

x squared+6x-4x-6.4=0
x(x+6)-4(x+6)=0
(x+6)(x-4)=0

2006-07-26 22:40:54 · answer #10 · answered by chocolate 3 · 0 0

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