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True or False?

2006-07-26 08:00:26 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

False in general. Putting on shoes and then putting on socks is different than putting on socks and then putting on shoes.

2006-07-26 08:14:55 · answer #1 · answered by mathematician 7 · 0 0

Technically, the answer is FALSE. In math, if a statement is not always true, then it must be considered false. This does not mean that the statement can never be true.

If f(x) and g(x) are inverse functions, then (f o g)(x) = (g o f)(x).

Most of the time, however, the composites are not equal.

2006-07-26 15:10:41 · answer #2 · answered by stevenatasu 1 · 0 0

None of the above. Sometimes true, sometimes false.

f(x) = x^2
g(x) = x^3 True

f(x) = x+5
g(x) = x+9 True

f(x) = x^2
g(x) = x+9 False

2006-07-26 15:37:04 · answer #3 · answered by Anonymous · 0 0

Give numerical values to test this equation.
f = 2
o= 3
g = 4
X =5
Left side of the equation: 120
Now, apply the same rule to the right side: 120

So, it is true.
This makes sense. Because they are multiplicants. It does not matter which order they are multiplied.

2006-07-26 15:31:34 · answer #4 · answered by Nightrider 7 · 0 0

False; consider this example: g(x)=2x and f(x)=4+x. (f o g)(x)=4+2x and (g o f)(x)=8+2x. Clearly not equal.

2006-07-26 15:06:49 · answer #5 · answered by gfmech 2 · 0 0

False. In (f o g)(x), x is plugged into g first, and the resulting value is plugged into f. In (g o f)(x), x is plugged into f first, and the resulting value is plugged into g.

2006-07-26 15:04:15 · answer #6 · answered by Anonymous · 0 0

False

let f(x)=2x
and g(x)=x^2

then (fog)(x) = f(g(x)) = f(x^2) = 2x^2
(gof)(x) = g(f(x)) = g(2x) = (2x)^2 = 4x^2

2006-07-26 15:03:06 · answer #7 · answered by Eulercrosser 4 · 0 0

I really like mathematician's answer. :)

2006-07-26 15:26:30 · answer #8 · answered by Jay H 5 · 0 0

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