Math questions..?

Question

I have no clue how to do this problem will someone please help me??



53 and 1 over 4 MINUS 3 over 8??


137 and 14 over 15 MINUS 15 and 51 over 120??



And heres another hard one for me.


find the products of the following. Show all work. Reduce anwsers to lowest terms.

1 x 1
_ _
3 4 it would be 1 over 3 times 1 over 4??




2 and 1 over 6 times 4 and 1 over 3
>??


can someone show me and explain how to do this?

Answer 1

53 and 1 over 4 MINUS 3 over 8?? 423/8
213/4-3/8=426/8-3/8=423/8
137 and 14 over 15 MINUS 15 and 51 over 120?? 14701/120
2069/15-1851/120=16552/120-1851/120=14701/120
while adding or subtracting mixed nos first convert the mixed nos into vulgar fractions and then reduce them both to the same denominator by taking LCM and the do the operation on the numerator
find the products of the following. Show all work. Reduce answers to lowest terms.
(1/3)*(1/4)
(1*1)/(3*4)=1/12
2 and 1 over 6 times 4 and 1 over 3
2 and 1 over 6 times 4 and 1over 3
=(13/6)(13/3)=169/18
can someone show me and explain how to do this?
first you convert the mixed nos into vulgar fractions.

Answer 2

The first is a division problem, you work it top to bottom:
53+1 divided by 4-3 divided by 8. 54 divided by 1 divided by 8.
The second is a division problem, but you can stop at 15-15 because it equals 0 and 0 divided by anything equals...?
The third one is a matter of straight multiplication numerator times numerator and denominator times denominator: 1 times 1 over 3 times 4. Your answer will be a fraction.
The fourth is a division problem, you work it top to bottom: 2 +1 divided by 6 times (4 +1)divided by 3. Without seeing the problem in the math book or what is requested, this is the best I can do. Is this algebra or straight arithmetic?