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Given that 9.09e20 molecules of XeFn weigh 0.311g, calculate n.

2006-07-26 06:27:40 · 1 answers · asked by melomane 4 in Science & Mathematics Chemistry

1 answers

First convert to moles by dividing by Avogadro's number,

N = 9.09 * 10^20 / 6.02 * 10^23 = 0.001510 mole

The molar mass of your substance is therefore

M = m / N = 0.311 / 0.001510 = 206.0 amu

Xe has mas 131.3, so for the fluor you have lef

206.0 - 131.3 = 74.66 amu

Each fluor contributes 19.0 amu, so we find

n = 74.66 / 19.0 = 3.93 ~ 4

The substance is therefore XeF4, xenon tetrafluoride.

2006-07-26 06:37:07 · answer #1 · answered by dutch_prof 4 · 2 0

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