Equals to an F on your next test.
2006-07-26 05:43:03
·
answer #1
·
answered by teh_sexi_hotttie 4
·
1⤊
0⤋
Because you have not given an equalto sign I am presuming you mean 4x^3 -8x^2 -12x=0
ie 4x(x^2 -2x -3) = 0, equating 4x = 0 we get x = 0
Solving x^2 -2x -3 = 0 by factors we get (x-3)(x+1) = 0
ie either x-3 = 0 which gives us x =3
or x+1 = 0 which gives us x = -1
Putting all three results together, x= 3, 0, -1
2006-07-26 12:51:23
·
answer #2
·
answered by SmartSpider 4
·
0⤊
0⤋
I presume you are factoring
4 x**3-8x**2-12x
= 4x(x**2-2x-3)
= 4x(x-3)(x+1)
2006-07-26 19:24:49
·
answer #3
·
answered by Mein Hoon Na 7
·
0⤊
0⤋
4x³ - 8x² -12x = 0
x(4x² - 8x - 12 = 0
Common factor x
x(2x - 6)(2x + 2)
x = 0
2x - 6 = 0
+6 +6
subtract 6 from both sidew
2x = 6
2x/2 = 6/2
Divide 2 from both sides
x = 3
- - - - - - - - - - - - - - - - - - - - -- - - -
2x + 2 = 0
-2 -2
Subtract 2 from both sides
2x = - 2
2x/2 = - 2/2
x = -1
- - - - - - - - - - - - - - - - - - -
The answer
X = 0
2x-6 = 3
2x + 2 = -1
2006-07-27 11:17:17
·
answer #4
·
answered by SAMUEL D 7
·
0⤊
0⤋
i will start with the solution ...
4x^3 -8x^2 -12x = 4x(x^2 - 2x -3) = 4x(x-3)(x+1)
2006-07-26 12:46:12
·
answer #5
·
answered by gjmb1960 7
·
0⤊
0⤋
4x^3 - 8x^2 - 12x
4x(x^2 - 2x - 3)
4x(x - 3)(x + 1) = 0
x = 0, 3, or -1
2006-07-26 20:58:39
·
answer #6
·
answered by Sherman81 6
·
0⤊
0⤋
I assume that the above is equal to zero. So just find your roots, factor out x so x=0 is one answer, then use your quadratic equation to find the other 2 roots.
2006-07-26 12:43:58
·
answer #7
·
answered by kdog 4
·
0⤊
0⤋
it has to equal to 0
factor out 4x
4x(x^2 - 2x -3) = 0
4x(x-3)(x+1)=0
x=0, 3, -1
2006-07-26 12:46:33
·
answer #8
·
answered by asdfjkl; 2
·
0⤊
0⤋
It should be equated first to zero..
2006-07-26 13:40:14
·
answer #9
·
answered by sobrangtangatangako 2
·
0⤊
0⤋
Where is your equal sign?
2006-07-26 12:43:01
·
answer #10
·
answered by jf_stanfield 2
·
0⤊
0⤋