Please be detailed
2006-07-26 05:27:53 · 10 answers · asked by franciscoeleodoro 1 in Science & Mathematics ➔ Mathematics
a = 2
B = -6
C = -20
=> X = [-B +/- SQUARE ROOT(B^2 -4AC)] / 2A
=> X = [-(-6) +/- SQUARE ROOT((-6)^2 -4(2)(-20))] / 2(2)
=> X = [6 +/- SQUARE ROOT(36 + 160)] / 4
=> X = [6 +/- SQUARE ROOT(196)] / 4
=> X = [6 +/- 14] / 4
=> X = [6 + 14] / 4 OR X = [6 - 14] / 4
=> X = 20 / 4 OR X = -8 / 4
=> X = 5 OR X = -2
2006-07-26 05:56:42 · answer #1 · answered by h_alshalchi 2 · 3⤊ 1⤋
x=5 or x=-2
2006-07-26 13:33:30 · answer #2 · answered by sobrangtangatangako 2 · 0⤊ 0⤋
2x2-6x-20 =0
dividing both sides by 2
x2 -3x -10 =0
sum of 2 numbers -3 and product = -10 they are -5 and 2
so (x-5)(x+2) =0
so x = 5 or -2
2006-07-26 19:27:47 · answer #3 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
Ok i dont know what a quadratic formula is because i am 13 but here's what i know of it
4-6x-20=0
16-6x=0
+16=+16
6x=16
x=16/6
x=2.6666666666666666666666666666666666666666666666667
2006-07-26 12:37:06 · answer #4 · answered by The Great Questioner 2 · 0⤊ 0⤋
Using the formula: (-b±âb²-4ac) / 2a
x = 5 and x = -2.
2006-07-26 12:37:05 · answer #5 · answered by Brenmore 5 · 0⤊ 0⤋
2x^2 - 6x- 20 = 0
x^2 - 3x - 10 = 0
(x-5) (x+2) = 0
now you figure out the rest... bye!
2006-07-26 12:41:52 · answer #6 · answered by ♥michele♥ 7 · 0⤊ 0⤋
2x^2 - 6x - 20 = 0
x = (-b ± sqrt(b^2 - 4ac))/2a
x = (-(-6) ± sqrt((-6)^2 - 4(2)(-20)))/(2(2))
x = (6 ± sqrt(36 + 160))/4
x = (6 ± sqrt(196))/4
x = (6 ± 14)/4
x = (20/4) or (-8/4)
x = 5 or -2
ANS : 5 or -2
2006-07-26 21:01:08 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋
x = ( -b +- sqrt( b^2 - 4ac ) ) / 2a
   = ( -(-6) +- sqrt( (-6)^2 - 4(2)(-20) ) ) / 2(2)
   = ( 6 +- sqrt( 36 + 160 ) ) / 4
   = ( 6 +- 14 ) / 4
x = 5
x = -2
2006-07-26 13:50:28 · answer #8 · answered by Anonymous · 0⤊ 0⤋
a=2, b=-6, and c=-20.
x=[-b +- sqrt(b^2 -4ac)]/2a
Now plug in. You can do the square root exactly to get your two roots.
2006-07-26 12:36:43 · answer #9 · answered by mathematician 7 · 0⤊ 0⤋
imposible because it's 44 I just know k because I have a A in math
2006-07-26 12:37:27 · answer #10 · answered by navydaugh 2 · 0⤊ 0⤋