2006-07-26 05:10:13 · 5 answers · asked by ashka e 1 in Science & Mathematics ➔ Mathematics
write as y = ....
(x-1)^2=12(y- x)
(1/12) *(x-1)^2 = y - x; (divided bith sides by 12)
(1/12) *(x-1)^2 + x= y ; ( added x to both sides )
uhhhmmm well i dont know it this is an answer to you question
maybe you want to know where the two parabolas intersect ?
1) (x-1)^2=12(y- x)
2) x=16y^2
substitute x = 16^y2 into 1)
this gives you an equation in y.
solve this y, gives you at most 2 y's
substitute these y's into 2) that will give you an x (2x's)
just like Thermo did.
hope this helps but i doubt .....
2006-07-26 05:14:20 · answer #1 · answered by gjmb1960 7 · 0⤊ 0⤋
Can you add some information? You've given us the equations of the parabolas, but you haven't told us what you're supposed to do with them. Graph them? Find the roots? Find the vertices and intercepts? Determine whether the parabolas open up or down?
2006-07-26 12:17:54 · answer #2 · answered by Jay H 5 · 0⤊ 0⤋
x=16y^2. Pace tis into (x-1)^2=12(y- x)
You get (16y^2-1)^2=12(y- 16y^2)
256y^4 - 32y + 1 = 12y^2 - 384y^3 + 3072y^4
Too heavy for me.
2006-07-26 12:15:51 · answer #3 · answered by Thermo 6 · 0⤊ 0⤋
wat r we supposed to find? make y the subject? o.O
1. y = [(x-1)^2 +12 x] / 12
2. y = root (x/16)
2006-07-26 12:14:46 · answer #4 · answered by woonie 3 · 0⤊ 0⤋
i don't no i can't do them yet
2006-07-26 12:17:12 · answer #5 · answered by ashlyn 1 · 0⤊ 0⤋