2006-07-26 04:21:38 · 7 answers · asked by astar 1 in Business & Finance ➔ Careers & Employment
well I think between 30-50 dollars hour, but they usually dont work that many hours.
2006-07-26 04:23:58 · answer #1 · answered by I love money 4 · 1⤊ 1⤋
The salary/remuneration for a particular job is the market value for a particular profession and designation at the city/town where the office is located. Job postings at websites like Monster, Yahoo HotJobs and Careerbuilder carry information about salaries. The Govt Dept of Labor, (www.bls.gov) Bureau of statistics has information about median salaries for different professions and details of additional compensation offered. Other online resources are salary.com and payscale. Your salary will also depend on your educational qualification and how you handle your career.
More details and links to relevant websites available at http://tinyurl.com/rndxq
2006-07-27 19:39:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It depends on what you mean by technician, how many years of experience you have, whether or not you have related education and where in the country you are. Try using a salary survey tool like those available through monster.com.
2006-07-26 04:37:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Depends on where you are and how much schooling you have... Here where I am they start out at $45.00 straight out of school and can get up to about $65 an hour (but they are salaried here.. that is just figureing an hourly rate.)
2006-07-26 04:25:31 · answer #4 · answered by mom_of_4 6 · 0⤊ 0⤋
varies a LOT.
in a mom and pop repair shop. 8 to 12 bucks per hour. so 16 to 24k per year.
in networking, 12 to 18 an hour.
in security 45 per hour and up.
2006-07-26 04:24:22 · answer #5 · answered by digital genius 6 · 0⤊ 0⤋
In Seattle or Bangalore?
2006-07-26 04:25:00 · answer #6 · answered by Anonymous · 0⤊ 0⤋
it all depends how good U R, and it takes allot experience to no what U do..if U good U can write your own ticket
2006-07-26 04:34:14 · answer #7 · answered by Anonymous · 0⤊ 0⤋