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Simple Harmonic Oscillator, Springs in Series and Parallel and Hooke's Law: Lab #12
2. By hanging additional masses from the Mass Hanger, adjust the total mass hanging from the Spring Balance to each of the values shown in the table. For each value, record the spring displacement.
3. Using the formula F = mg, determine the total weight in newtons for each set of masses that was used. Record your results in the table. (To get the correct force in newtons, you must convert the mass values to kilograms before multiplying by g.)
NOTE: When using hanging weights to measure force, the term "gram" is often used as if it were a unit of weight. There is no harm in this, as long as the differcnce between weight and mass are well understood. That is:
Weight = Mass x g(the Acceleration due to gravity).
Weight is a force that depends on mass and gravity. If the gravitational constant changes--on the moon, for example--the weight changes as well, but the mass remains the same.
Calculations
1. Using, the program"Graphical Analysis" have the computer plot a Spring Displacement vs. Force graph. Be sure the computer connects the data points and draws in a regression line. Also have the computer put your initials next to the units.
2. Determine the slope of the line by showing the rise and run on your graph. Be sure to show calculations also on your graph.
3 . Take the reciprocal of the slope, this is the spring constant for the spring used in the spring balance.
Spring Constant = _______________Newton/cm
2006-07-26 01:06:03
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answer #1
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answered by karlzrakizta_10 1
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In physics, Hooke's law of elasticity is an approximation which states that the amount by which a material body is deformed (the strain) is linearly related to the force causing the deformation (the stress). Materials for which Hooke's law is a useful approximation are known as linear-elastic or "Hookean" materials.
For systems that obey Hooke's law, the extension produced is proportional to the load:
F = -kx
where F is the restoring force exerted by the spring,
x is the distance the spring is elongated by,
k is the spring constant or force constant of the spring.
When this holds, we say that the spring is a linear spring.
2006-07-26 08:15:12
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answer #2
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answered by Guru 3
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Hookes law states basically that the extension of a spring is mathematically proportinal to the weight added, bearing in mind this is not true if the spring is deforming due to too much weight. Therefore it is useful for measuring forces because you can calculate the extension, or measure the extension and be able to work out the weight of the object by the extension, or what the extension would be...by the weight of the object.
e.g. if a spring extends 3mm per 50 grams, it would be 6 mm at 100g... or 12 mm at 200g or 24mm at 400g or 27mm at 450grams.
2006-07-26 08:18:57
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answer #3
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answered by Anonymous
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the lenght is proportional to tension
tut si lenght ut si tension -- this was encrypted and published
after arranging the alphabets/characters in ascending order
In a spring the lenght of the spring is proportional to the "weight"
and this needs calibration to maintain accuracy
2006-07-26 08:06:34
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answer #4
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answered by sen t 1
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