(x+1)over (x-5) -2 perform the indicated operations and simplify the given expression?

Answer 1

Well first what you need to do is make the "2" subtractable. In order to do this, make the denominators equal so subtraction is possible. Multiply "2" by "1", which is still equal to two; however, "1" is now "(x-5)/(x/5)". This reduces to one, so multiply and then you will have:

x+1 (2)(x-5)
----- - -----------
x-5 (x-5)

which, when multiplied, becomes

x+1 (2x-10)
----- - -----------
x-5 (x-5) .

So, since the denominator is the same, you can do this:

(x+1) - (2x-10)
--------------------
(x-5)

which becomes

(x+1) + (-2x + 10)
------------------------
(x-5) .

Then, combine like terms.

-x + 11
----------
x-5 .

Simplify depending on how your teacher/textbook wants the format...

-x + 11 11 - x
--------- OR --------
x-5 x-5 .

There you go. Sorry about the off center work!!

Answer 2

(x + 1) / (x - 5) - 2
(x + 1) / (x - 5) - (2)(x - 5) / (x - 5)
(x + 1 - 2x + 10) / (x - 5)
(-x + 11) / (x - 5)

Answer 3

((x + 1)/(x - 5)) - 2
((x + 1)/(x - 5)) - ((2(x - 5))/(x - 5))
((x + 1) - 2(x - 5))/(x - 5)
(x + 1 - 2x + 10)/(x - 5)
(-x + 11)/(x - 5)

Answer 4

(2x + 2)/(x+a million) + a million/x Set this equivalent to 0 (2x+2)/(x+a million) + a million/x = 0 Now subtract a million/x from each and every part (2x+2)/(x+a million) = -a million/x Now multiply both part by using x (2x^2+2x)/(x+a million) = -a million Multiply both part by using x-a million 2x^2+2x = -(x+a million) Now upload x+a million to each and every part 2x^2+2x+x+a million = 0 carry jointly your like words 2x^2 + 3x +a million

Answer 5

try to write more mathematically in future.