4!
I knew I could do it.
Damn ma hope yer proud
2006-07-25 21:13:53
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answer #1
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answered by rainphys 2
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(2x + 2)/(x+1) + 1/x Set this equal to 0
(2x+2)/(x+1) + 1/x = 0 Now subtract 1/x from both sides
(2x+2)/(x+1) = -1/x Now multiply both side by x
(2x^2+2x)/(x+1) = -1 Multiply both side by x-1
2x^2+2x = -(x+1) Now add x+1 to both sides
2x^2+2x+x+1 = 0 Collect your like terms
2x^2 + 3x +1
2006-07-25 20:49:29
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answer #2
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answered by Anonymous
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do you mean: [(2x+2/x+1) + 1] / x?
[2(x+1)/(x+1) + 1] / x = (2 + 1) / x = 3/x.
2006-07-25 18:37:24
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answer #3
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answered by the redcuber 6
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(2x+2)/(x+1) + 1/x
= [(2x+2)(x) + (x+1)]/(x+1)(x)
=(2x^2+2x + x+1)/(x^2 + x)
=(2x^2+3x+1)/(x^2+x)
=[(2x+1)(x+1)]/[(x)(x+1)]
=2 + 1/x
2006-07-25 18:55:45
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answer #4
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answered by sumone^^ 3
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((2x + 2)/(x + 1)) + (1/x)
(2(x + 1)/(x + 1)) + (1/x)
2 + (1/x)
((2x)/x) + (1/x)
(2x + 1)/x
2006-07-26 03:02:54
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answer #5
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answered by Sherman81 6
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(Please ignore periods.. they are to displace the calculations accordingly)....
Reversed Measures: Quantum Realty and Proposed Theory:
... 2x + 2...... 4x
... --------..... ------
.... x + 1...=....1x
.... ------- ..... ------
....... x............. x
Checked Answer:
.. x = 1 * 1x = 1x^2
...... 4x
.... -------- = 4x * 1x^2 = 4x^2
..... 1x^2
True Answer & work to show:
Of 4x * 1x^2 = 4x^2 =
........ 2 ( + 1 )................... ( 2 + 1 )
. [. ----------------. + 1. ] =. --------------
......... x + 1............................ x
... 2 ( x + 1 )....... + 1..... 2 + 1........ 3
.. --------------. +. ------ = --------- = ------
..... ( x + 1)........... x........ x............ x
Answer is:
......... 3
.... -----------
......... x
Hope this helped.... Good Day
--Rob :)~
2006-07-25 18:48:11
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answer #6
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answered by stealth_n700ms 4
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try to write more mathematically in future.
2006-07-25 20:22:11
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answer #7
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answered by rajesh bhowmick 2
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You REALLY need to get laid.
- Regards,
Ward
2006-07-25 18:36:26
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answer #8
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answered by Anonymous
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