Sorry I didn't get this hard one
2006-07-25 18:13:31 · 5 answers · asked by Pipos 1 in Science & Mathematics ➔ Mathematics
find the values for the given expression is undefined?
2006-07-25 18:19:46 · update #1
It's undefined for x = 0 or 1 or -1. Those are the zeros of the denominator. Good luck!
2006-07-25 18:16:26 · answer #1 · answered by anonymous 7 · 0⤊ 0⤋
x^3 - x = x(x^2-1) = x(x+1)(x-1)
So (x-7)/ (x^3-x) = (x-7) / (x(x+1)(x-1))
which is discontinuous(undefined) at x=0, x= -1 and x=1.since the denominator would be zero, and division by 0 is undefined.
2006-07-26 01:23:47 · answer #2 · answered by Jimbo 5 · 0⤊ 0⤋
set denominator equal to zero x(x^2-1) = 0
x = 0, 1, -1
2006-07-26 01:22:30 · answer #3 · answered by mdc 2 · 0⤊ 0⤋
x-7/(x(x-1)(x+1))
then undefind mean x(x-1)(x+1)<>0
x=0 x=1 x=-1 are the undefind value of x
2006-07-26 02:14:57 · answer #4 · answered by sanjeewa 4 · 0⤊ 0⤋
=(x-7) / x³ - x
u can't expect an answer for this problem.
2006-07-26 08:44:38 · answer #5 · answered by teenwitch 2 · 0⤊ 0⤋