2006-07-25 18:03:27 · 7 answers · asked by Pipos 1 in Science & Mathematics ➔ Mathematics
Ahem... that is (2x+1)(4x²-2x+1), not the other way around.
2006-07-25 18:09:55 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
8x^3 +1 = 0 <=> x^3 = -1/8 <=> x = -1/2
thus x+1/2 is a divisor of 8x^3 +1, dividing gives
(x+1/2)(8x^2 -4x + 2)
2006-07-25 20:52:57 · answer #2 · answered by gjmb1960 7 · 0⤊ 0⤋
If your expression is in the field R[x], your factors would be
(2x+1)(4x^2-2x+1)
If your expression is in the field C[x], your factors would be
(2x+1)(8x-1-i(sqrt of 3))(8x-1+i(sqrt of 3))
2006-07-25 20:39:40 · answer #3 · answered by dbpygrp 1 · 0⤊ 0⤋
8x^3+1 = (2x)^3+1 ;8=2^3 & 1=1^3
=(2x+1)(4x^2 -2x +1)
2006-07-25 18:20:06 · answer #4 · answered by sanjeewa 4 · 0⤊ 0⤋
8x^3 + 1 = (2x + 1)(4x^2 - 2x + 1)
2006-07-26 03:06:33 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
a^3 +b^3 = (a+b)(a^2 - ab +b^2)
here a = 2x , b=1
answer is (2x+1)(4x²-2x+1) as given by second answer
2006-07-25 18:15:40 · answer #6 · answered by qwert 5 · 0⤊ 0⤋
(2x+1)(2x^2-4x+1)
**sum of 2 cubes
2006-07-25 18:08:10 · answer #7 · answered by aimsnapfall 2 · 0⤊ 0⤋