2006-07-25 18:02:30 · 6 answers · asked by Pipos 1 in Science & Mathematics ➔ Mathematics
It's undefined for x = 3 or -3, because that would make the denominator zero. You can't divide by zero.
2006-07-25 18:07:00 · answer #1 · answered by anonymous 7 · 0⤊ 0⤋
It is undefined if the denominator is zero. The denominator in this case is x^2 -9. x^2 -9 = 0 to make the expression undefined, x = 3 or -3.
2006-07-25 18:09:09 · answer #2 · answered by G.V. 6 · 0⤊ 0⤋
Actually it goes to infinity at these points. The denominator is of the form A^2 - B^2 which can be written (A+B)(A-B)
ie (x+3)(x-3). So if you were to draw this graph at the points where x = 3 or x = -3 the graph would go to infinity but at points close to this the graph is actually a finite number.
2006-07-25 20:36:45 · answer #3 · answered by blind_chameleon 5 · 0⤊ 0⤋
x= 3, -3
2006-07-25 18:06:23 · answer #4 · answered by aimsnapfall 2 · 0⤊ 0⤋
x^2-9 is (x+3)(x-3) set those equal to zero so the answer is 3 and -3
2006-07-25 18:07:53 · answer #5 · answered by mdc 2 · 0⤊ 0⤋
1/(x^2 - 9) = 1/((x - 3)(x + 3))
x cannot equal 3 or -3
2006-07-26 03:06:57 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋