solve 3x2 - 5x - 2 =0 using the quaadratic formula?

Question

plEase be detailed

Answer 1

The quadratic formula solves Ax^2 + Bx + C = 0 for x as
x = [-B +or- sqrt(B^2 - 4*A*C) ]/ 2*A

in this case A=3, B= -5, and C = -2

so x = [-(-5) +or- sqrt((-5)^2 - 4*3*(-2)) ]/ 2*3
= [5 +or- sqrt(25 + 24) ] / 6
= [5 +or- sqrt(49) ] / 6
= [5 +or- 7 ] / 6
= 5/6 +or- 7/6
= 12/6 or -2/6
= 2 or -1/3

Answer 2

The quadratic formula Ax^2 + Bx + C = 0 solves for x as
x = [-B +or- sqrt(B^2 - 4*A*C) ]/ 2*A

here A=3, B= -5, and C = -2 and

x = [-(-5) +or- sqrt((-5)^2 - 4*3*(-2)) ]/ 2*3
= [5 +or- sqrt(25 + 24) ] / 6
= [5 +or- sqrt(49) ] / 6
= [5 +or- 7 ] / 6
= (5+7)/6 or (5-7)/6
= 12/6 or -2/6
=2 or -1/3

So x got values 2 and -1/3. If you put these values in the place of x in that equation you may know it is true.

Answer 3

Assuming you mean 3x^2-5x-2=0
then x=2

Answer 4

The quadratic formula is:
(-b (+ or -) square root of (b^2-4ac))/2a

and refers to the equation:
ax^2 + bx + c = 0

a= 3
b= -5
c = -2

Plug 'em in, and figure it out!

Answer 5

6-5x-2=0
-5x= -6+2
-5x= -4
5x=4
x= 0.8

Answer 6

My 8 year old daughter could figure this out if I gave her the formula. Don't you think that you could do the same?

Here we go;

a = ?
b = ?
c = ?

plug them in!!!

Answer 7

solve it ur self j a c k a s s....y would u put a question like that on here

Answer 8

(5 +/- 7) / 6 = -1/3 or +2
You can tell at a glance, almost.
Now go answer mine.
http://answers.yahoo.com/question/index;_ylt=AnE.Qyq3H2HxDRg8uBJxVM_sy6IX?qid=20060725172009AAi7A3k

Answer 9

X=B+- B2-4AC AND SO ON
I REALLY DONT FEEL LIKE DOING MATH RIGHT NOW. SORRY

Answer 10

3x^2-5x-2=0
a=3, b=-5, c=-2
x=(-b+(b^2-4ac)^0.5)/2a and (-b-(b^2-4ac)^0.5)/2a
(b^2-4ac)^0.5=((-5)^2-4*3*(-2))^0.5=(49)^0.5=7
x=(-(-5)+7)/(2*3) and (-(-5)-7)/(2*3)
x=(12/6) and (-2/6)
x=2 and -1/3(negative one third)