I don't understand what you want to solve with this.
64x^2 - 9y^2 = ????
Are you trying to solve for x and y, or are you trying to factor this?
If you are just factoring,
take the square root of 64x^2
sqrt(64x^2) = 8x
take the square root of 9y^2
sqrt(9y^2) = 3y
2.
Now, use this information to factor. How do we do this? Lets take a look at other examples.
x^2 - 4 = (x + 2) (x - 2), we see that sqrt(x^2) = x and sqrt(4) = 2
4x^2 - 4y^2 = (2x + 2y) (2x - 2y)
Thus, using the information we have
64x^2 - 9y^2 = (8x + 3y) (8x - 3y)
2006-07-25 17:43:54
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answer #1
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answered by polloloco.rb67 4
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64x²-9y²=(8x-3y)(8x+3y)
By the way, the standard computer notation for writing exponents is to use the carat symbol '^', which is produced by pressing the shift key and the number 6 (on your keyboard, not your keypad). Thus, you might write 64x^2-97y^2, which is much simpler than writing out (exponent) all the time. Alternatively, you can use the unicode superscript characters, as I did, although caution must be exercised when doing this because not all fonts include such characters, and you don't want people to have to guess what that big ugly box is.
2006-07-26 00:42:25
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answer #2
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answered by Pascal 7
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the graph of 64x^2 - 9^y2 = R^2 ; R given number is an ellips is kind of egg
2006-07-26 03:57:52
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answer #3
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answered by gjmb1960 7
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64x^2 - 9y^2 = (8x - 3y)(8x + 3y)
2006-07-26 10:07:57
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answer #4
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answered by Sherman81 6
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I am not sure what the (exponent) words mean but the answer is
128x - 18y for sure
2006-07-26 00:41:00
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answer #5
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answered by truman 1
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(8x)^2-(3y)^2
=(8x-3y)(8x+3y)
2006-07-26 02:11:18
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answer #6
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answered by sanjeewa 4
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